For the acidified chromate equilibrium, what effect would you predict if you diluted the system (meaning you add just pure water to a mixture that had been at equilibrium)?

If 0.54 molmol of Br2Br2 and 1.23 molmol of Cl2Cl2 are introduced into a 3.0-LL container at 400 KK, what will be the equilibrium concentration of Br2Br2? If 0.54 molmol of Br2Br2 and 1.23 molmol of Cl2Cl2 are introduced into a 3.0-LL container at 400 KK, what will be the equilibrium concentration of Cl2Cl2? If 0.54 molmol of Br2Br2 and 1.23 molmol of Cl2Cl2 are introduced into a 3.0-LL container at 400 KK, what will be the equilibrium concentration of BrClBrCl?

Suppose a 250. mL flask is filled with 0.60 mol of SO₂ and 1.0 mol of SO3. This reaction becomes possible: 2SO₂(g) + O₂(g) — 2SO3(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O₂. You can leave out the M symbol for molarity. initial change equilibrium SO₂ 0₂ 0 X 0 SO₂ 0 010 X Ś

During an experiment, O.257 mol of H2 and 0.257 mol of I2 were placed into a 1.28 liter vessel where the reaction H2(g) + 12(g) 2 2HI(g) came to equilibrium. For this reaction, Kc = 49.5 at the temperature of the experiment. What were the equilibrium concentrations of H2, 12, and HI? [H2] = M %3D [12] = M [HI] = i M

2) Based on the information below, determine the value of the unknown equilibrium constant, Kc. 2 NOCl (g) « 2 NO (g) + Cl2 (g)​​​Kc = 2.4 x 10-7 1/3 Cl2 (g) + 2/3 NO (g) « 2/3 NOCl (g)​​Kc = ?

True/False. Explain your answer in one sentence or less.   In an equilibrium process, the concentrations of products and of reactants are equal. The value of the equilibrium constant for a given reaction depends on the initial concentrations of reactants. Large value for equilibrium constant K means the reaction will be less complete at the equilibrium point. The concentration of a pure solid is left out of an equilibrium constant expression but a pure liquid is included.

Consider the equilibrium system described by the chemical reaction below. Determine the concentration of O, at equilibrium by writing the equilibrium constant expression and solving it. Complete Parts 1-2 before submitting your answer. = 2 H₂O(g) 2 H2(g) + O̟₂(g) 1 2 NEXT At this temperature, the Kc = 2.4 × 103 and the equilibrium concentrations of H2O and H2 are 0.11 M and 0.019 M, respectively. If [x] represents the equilibrium concentration of O2, set up the equilibrium expression for Kc to solve for the concentration. Each reaction participant must be represented by one tile. Do not combine terms. Кс = 2' = 2.4 × 103 > RESET [0.11] [0.019] 2[0.11] 2[0.019] [0.11]² [0.019]² [x] [x]² [2x] [2x]²

Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric chemistry. It can react with itself to form another form of NOx, dinitrogen tetroxide. A chemical engineer studying this reaction fills a 100L tank with 27. mol of nitrogen dioxide gas. When the mixture has come to equilibrium he determines that it contains 9.0 mol of nitrogen dioxide gas. The engineer then adds another 6.8 mol of nitrogen dioxide, and allows the mixture to come to equilibrium again. Calculate the moles of dinitrogen tetroxide after equilibrium is reached the second time. Round your answer to 2 significant digits. mol

Write the equilibrium expression, in terms of pressure, for the formation of ammonia equilibrium.