Find the x- and y-coordinates of the center of gravity for the boomerang as in (a) of the figure below, modeling the boomerang as in (b) of the figure, where each uniform leg of the model has a length of 0.232 m and a mass of 0.290 kg. (Note: Treat the legs like thin rods. Enter your answers in m.) HINT a m m 40.0° 40.0°
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- E Boview Find the force that the floor exerts on each of his feet, assuming that both feet exert the same force. To strengthen his arm and chest muscles, a 79-kg athlete 2.0 m tall is doing a series of push-ups as shown in the figure below (Figure 1). His center of mass is 1.20 m from the bottom of his feet, and the centers of his palms are 30.0 cm from the top of his head. Express your answerkn newtons. F- 125.24 Submit Previou Answers Reguest Answer X Incorrect; Try Again; 4 attempts remaining Part B Figure 1 of 1> Find the force that the floor exerts on each of his hands, assuming both palms exert the same force. Express your answer in newtons. -20m F- 114 -300 on Submit Previous Answers Bequest Answer X Incorrect; Try Again; 5 attempts remaining P PearsonFind the x- and y -coordinates of the center of gravity for theboomerang in Figure P8.12a, modeling the boomerang as inFigure P8.12b, where each uniform leg of the model has alength of 0.300 m and a mass of 0.250 kg. (Note: Treat the legslike thin rods.)Find the x - and y -coordinates of the center of gravity for the boomerang in Figure P8.12a. modeling the boomerang as in Figure P8.12b, where each uniform leg of the model has a length of 0.300 m and a mass of0.250 kg. (Note: Treat the legs like thin rods.)
- Find the x and y-coordinates of the center of gravity of a 4.00-ft by 8.00-ft uniform sheet of plywood with the upper right quadrant removed as shown in the figure below. Hint: The mass of any segment of the plywood sheet is proportional to the area of that segment.A carpenter's square has the shape of an L as shown in the figure below. Locate its center of gravity. (Take (x, y) = (0,0) at the intersection of d₁ and d₁. Assume d₁ = 19.0 cm, d₂ = 2.00 cm, d3 = 2.00 cm, and d4 = 15.0 cm.) X You can consider the carpenter's square to consist of two rectangles positioned at 90 degrees to each other., How do you determine the center of mass of an object made up of extended objects?) cm L dz d4 Enter a number.In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as shown in the figure here. One cord makes the angle 8 = 34.4 with the vertical; the other makes the angle o = 55.6 with the vertical. If the length L of the bar is 3.4 m, compute the distancex from the left end of the bar to its center of mass. com
- A uniform plank of length 2.00 m and mass 30.0 kg issupported by three ropes, as indicated by the blue vectors inFigure P8.27. Find the tension in each rope when a 700.-Nperson is d = 0.500 m from the left end.The figure below shows a human arm that weighs 41.10 N. The arm is extended outward and is motionless. The gravitational force Fg on the arm acts at point A, a distance of 0.2900 m from the shoulder joint, which is represented by point O. The shoulder pushes down and to the right on the humerus bone of the arm with a force Fs at point O, at an angle ? as shown. The deltoid muscle pulls back on the arm toward the shoulder with a tension force Ft. This tension force acts at a point 0.08000 m to the right of point O, and it is directed up and to the left, at a 12.00° angle with respect to the horizontal. An arm is extending horizontally to the right with a cutout that shows muscles in the upper arm. A horizontal dashed line extends along the bottom of the muscles and another along the top. Point O is labeled at the left end of the arm on the lower horizontal line. An unlabeled point lies 0.080 m horizontally to the right of point O. Point A lies 0.290 m horizontally to the right of point…The device shown in the figure below is one version of a Russell traction apparatus. It has two functions: to support the injured leg horizontally and at the same time provide a horizontal traction force on it. This can be done by adjusting the weight W and the angle θ. For this patient, his leg (including his foot) is 90.0 cm long (measured from the hip joint) and has a mass of 11.4 kg. Its center of mass is 41.0 cm from the hip joint. A support strap is attached to the patient's ankle 13.0 cm from the bottom of his foot. 1) What weight W is needed to support the leg horizontally? Express your answer in newtons. 2) If the therapist specifies that the traction force must be 16.0 N horizontally, what must be the angle θ? Express your answer in degrees. 3) What is the greatest traction force that this apparatus could supply to this patient's leg? Express your answer in newtons. 4) What is θ in that case? Express your answer in degrees.
- Introduce an appropriate coordinate system and find the center of mass of the planar lamina. (The answer depends on the position of the coordinate system. Round your answers to two decimal places.) ã, V) = (_ y 8. X. 8 24The forces exerted by the bicep muscle and acting on the elbow when a 12 kg barbell is being curled can be modeled based on the diagram above. The bicep muscle can be treated as a vertical cable. The mass and length of the forearm are 2 kg and 32 cm, respectively. The center of mass of the forearm is a distance of 14 cm from the point P, while the bicep connects to the forearm at a point 4.5 cm from P. a) Determine the tension in bicep muscle and the force of the humerus acting downward on the elbow at point P. b) Assuming the tension in the bicep muscle continues to be oriented vertically, determine the tension in the bicep muscle and the force acting at P after the barbell has been raised by an angle of 30 degrees relative to the horizontal.In the figure below, the CG of the pole held by the pole vaulter is 2.04 m from the left hand, and the hands are 0.713 m apart. (Assume the vaulting pole has a mass of 2.52 kg.) Calculate the force (in N) exerted by his right hand. (Enter the magnitude.)