Estimated effect size (relative to model intercept) Male reproductive success (adults) 0.3- -0.3- -0.6- -0.9- **tt Hot Hot HotHop HopHop b 2.0- 1.5- 1.0- 0.5- 0- Male survival HotHot HotHop Hop Hop RXFP2 genotype 0.2- 0.1- 0- -0.1- Male fitness Hot Hot HotHop HoPHOP 4. Interpret figure a, b or c. Genotypes: Hot Hot = big horn male HOPHOP = small horn male
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- 4G 4G 13:44 03 .. O NC Y 46: 13 KB/dtk LTE2 Google Lens * Indonesia Inggris 9. A yellow base color-normal wing (BBCC) parakeet is bred with a white base color-clear nine utih from ya wing (bbcc) parakeet to produce a yellow base color-normal wing (BbCc) u): but, parakeet. Furthermore, fellow descendants of F, are mated. From these crosses, the percentage of probability in F, that a parakeet appears that has the same genotype as its parent which is homozygous dominant .... is. a. 56,25% 18,75% d. 6,25% C. b. 25% gan 10. Heterozygous red fish are mated with white fish. It is known that red is dominant over white. From these gan may tih crosses, 48 fish were produced. The possible number of red fish with a genotype like the parent is as much as .. a. 12 tails Rr. 24 tails C. b. 18 tails me d. 48 tails B. Do the following questions! 1. A bird farmer wants to have a vellow parakeet. Known genotype and phenotype in parakeets as follows. PP: parakeet is green. Pp: a blue parakeet ah air an…ard | Climax-Scotts VA e Genes: The Heredity Code: Mas MVA High School Curriculum S x + f1.app.edmentum.com/assessments-delivery/ua/mt/launch/49419269/858302444/aHR0cHM6Ly9mMS5hcHAUZWRtZW50dW0uY29tL2xlYXJuZXItdWkvc2V... A cation 4▾ Seesaw e Edmentum® Learni... Genius Next O Genes: The Heredity Code: Mastery Test Select the correct answer from each drop-down menu. Offspring inherit genes from their parents, and these genes determine their physical characteristics. According to the law of a heterozygous organism has about a allele. entum. All rights reserved. Search assortment genetics segregation Reset Next chance of producing gametes with the recessive SubmitW O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.
- Trivla Game Show _Make Your Own Tri ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566 Dillon WF g Aa v Done In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a guinea pig that has black, rough hair? (Select all that apply.) O BBRR BBRr BBrr BBRR BbRr O bbRR O bbRr O bbrr O Black O White O Rough OSmooth O Rough O SmoothPlease do this for me!! I would gladly appreciate it. Write one results sentences that describe what the boxplot shows (discuss variation, median, mean, and the statistical significance). Include important information about how the data was generated. Write one discussion sentences that interpret what the boxplot shows. What do you think the biological significance of the result is?11.0 G. fortis 10.0- 1978 1976 9.0F 8.0 8.0 9.0 10.0 11.0 Midparent bill depth (mm) Geospiza is a genus of finches that inhabit the Galapagos Islands. In 1976, finches were grouped together based on the average depth of their bills. The data from the first generation of grouped finches are plotted on the X-axis. The bill depths of the offspring from each group are plotted on the Y-axis. In 1978, the experiment was repeated after a drought on the Galapagos Islands. The red line represents the data from 1976 and the blue line represents the data from 1978. The slope of both the red line is 0.90 and the slope of the blue line is 0.90. Was there any change in the heritability of the bill depth trait after the drought? Explain your reasoning. Offspring bill depth (mm)
- help needed with all of them please A pesticide resistance allele was at a frequency of 50% in a population of flies. The pesticide was no longer effective because of the prevalence of resistant flies. Ranchers decided to stop using the pesticide, and in 20 years the resistance allele dropped to a frequency of 5%. The allele is autosomal, affects fitness in an additive fashion, and there are two fly generations per year. a) Explain in 1—2 sentences why natural selection may have caused a decrease in the frequency of the resistance allele. b) What is the selection coefficient acting against homozygotes for the resistance allele (in the absence of the pesticide)? c) What was the frequency of the resistance allele one generation after ranchers stopped using the pesticide (i.e., after one generation of viability selection)? Assume that the population was in Hardy-Weinberg equilibrium when ranchers stopped using the pesticide and the population underwent random mating. d) The effective…Odds Ratio (Estimated Relative Risk) 1. In a fictitious case-control study of male farm workers, 15 cases of low fertil- ity were selected and compared to 285 male farm workers in the same fields with normal fertility (control subjects). Researchers noted whether the workers handled pesticides or not. They found that 10 of the cases had handled pesti- cides, and only 90 of the controls had handled pesticides. Calculate the odds ratio (estimated relative risk) of low fertility associated with handling pesticides. a. First fill in the 2x2 table Handled pesticides? Yes No b. Now calculate the odds ratio. Cases Controls .)/(______ 2. Fifty residents of a small town were identified with E. coli infections. An investi- gation of 25 of these patients and 40 well residents of the same town revealed that many of the patients had eaten spinach from the local market in the week before the onset of illness. Of the control subjects, fewer had eaten spinach in the same time period. = Calculate the…Plasticity-10601931 Tools Add-ons Help Last edit was seconds ago ext Arial BIU A 10 6 1. The ability to grow differently colored fur based on the season provides Arctic foxes with a selective advantage. What do you think that is? 2. The Arctic fox exhibits "phenotypic plasticity." To understand what that means, let's first define the following terms: 2a. Phenotype: 2b. Plasticity: 3. Example 2: The American Peppered Moth caterpillars (Biston betularia cognataria) are able to Now, let's examine a couple more examples of phenotypic plasticity. Support | Schoology Blog I PRIVACY POLICY !!!
- 00 Dute Dec. 12 Extra Credit Punnett Square Worksheet Select 5 of the 6 scenarios to complete this activity. You will only be graded on the 5 you complete. 1. Brown eyes is a dominant trait for eye color. A woman with dark brown eyes (BB) has children with a man with blue eyes (bb). What are the eye color possibilities of the offspring? Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes 2. In Mendel's monohybrid cross of pea plants what was the result of crossing a plant with yellow pods (Yy) and a plant with yellow pods (Yy). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes 3. When an offspring's phenotype is a combination of the parents' phenotypes it is called incomplete dominance. Both the alleles are expressed. A cross between a radish plant that produces round radish and a radish plant that produces oblong radish results in producing oval radish (heterozygous genotype). What is…I need help in table 2 & 3 please Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 433.875 129.875 16789.68 38.69 Disease, Female 267 433.875 166.875 26855.01 61.89 WT, Male 285 144.625 140.375 19705.14 136.25 WT, Female 301 144.625 156.375 24453.15 156.37 Total 1157 1157 393.20 DF 3 p-value 7.84 Expected progencies as per SLR MOI’s = 1:1 for both male and female Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 289.25 14.75 217.56 0.75 Disease, Female 267 289.25 22.25 495.06 1.85 WT, Male 285 289.25 4.25 18.06 0.06 WT, Female 301 289.25 11.75 138.06 0.46 Total 1157 1157 3.12 DF 3 p-value 7.84 Progenies are following SR MOI’s that parents have genotypes and progenies in ratio 1:1 In Table 2,…inate S_Q1_Science_Biology_2022-2023 Question 1 200 TIDO D D BO 70 60 550 40 30 20 10 OF 0 5 X me graph shows the growth of the P caudatum population when it is grown separately. P. caudatum Alone 250 200 150 5 V 10 Time (days) Q Zoom 10 Time (days) 15 15 The graph shows the growth of the P. aurelia and P. caudatum populations when they are grown together. Both Species Grown Together 20 2022 Illuminate Education TM, Inc. Question 1 Which statement is supported by the graphs? A A B C D Accessibility Tools Signed in as: Zavion Ma Q Review/✔ Finish T ABG P. caudatumrand P. aurelia competed equally for resources. P. aurelia and P. caudatum did not compete for resources. P. aurelia was better able to compete for resources than P. caudatum P. caudatum was better able to compete for resources than P. aurelia Z