Drawing B INSTRUCTIONS: USE M12 BOLTS GRADE 4.6/5 INCLUDE BOLT GAUGE DISTANCES AND EDGE DISTANCES GUSSET PLATES FROM 8PL GUSSET PLATE TO BE SUNK BETWEEN ANGLES ALONG TOP AND BOTTOM FACES BY 10MM MINIMUM GAP BETWEEN MEMBERS TO BE 20mm WELDING SIZES: FOR 1/65x50x6 UA USE 120 OF 6mm FILLET EACH END FOR 1/100x75x10 UA USE 150 OF 8mm FILLET EACH END INTERMITTENT WELDS BOTH SIDES OF BOTTOM CHORD 110x6FL 220 BASE PLATE DRILL FOR 2/M12 BOLTS 55 2/1007510UA-UM 2/65×50×6 UA JL-LLV EXERCISE 2: SHEET 1 FULL TRUSS ELEVATION (125) SHEET 2: LINE DRAWING (125) AND MEMBER LIST INCLUDING MEMBERS, PLATES AND BOLTS. SHEET 3: JOINT DETAILS A, B, C & D (15) INCLUDING ALL NECESSARY DIMENSIONS AND DETAILS 2/550T-LLM WT-LP3/Z 2/65+506 UA CENTRELINE DIMENSIONS SYMMETRICAL ABOUT -LLV 7500 CTOC TRUSS HALF-ELEVATION

Drawing B INSTRUCTIONS: USE M12 BOLTS GRADE 4.6/5 INCLUDE BOLT GAUGE DISTANCES AND EDGE DISTANCES GUSSET PLATES FROM 8PL GUSSET PLATE TO BE SUNK BETWEEN ANGLES ALONG TOP AND BOTTOM FACES BY 10MM MINIMUM GAP BETWEEN MEMBERS TO BE 20mm WELDING SIZES: FOR 1/65x50x6 UA USE 120 OF 6mm FILLET EACH END FOR 1/100x75x10 UA USE 150 OF 8mm FILLET EACH END INTERMITTENT WELDS BOTH SIDES OF BOTTOM CHORD 110x6FL 220 BASE PLATE DRILL FOR 2/M12 BOLTS 55 2/1007510UA-UM 2/65×50×6 UA JL-LLV EXERCISE 2: SHEET 1 FULL TRUSS ELEVATION (125) SHEET 2: LINE DRAWING (125) AND MEMBER LIST INCLUDING MEMBERS, PLATES AND BOLTS. SHEET 3: JOINT DETAILS A, B, C & D (15) INCLUDING ALL NECESSARY DIMENSIONS AND DETAILS 2/550T-LLM WT-LP3/Z 2/65+506 UA CENTRELINE DIMENSIONS SYMMETRICAL ABOUT -LLV 7500 CTOC TRUSS HALF-ELEVATION

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QUESTION 11 3. check the capacity of the shear connection. A992: Fy=50ksi, Fu=65ksi A36: Fy=36ksi, Fu=58ksi effective bolt hole diameter = bolt hole + 1/16" beam properties: tw=0.295 in. Fexx=70ksi what is the weld capacity in kips? (2 decimal places)
A bolted connection shown is made up of 2L150 x 100 x 9.5 mm. The angle is made of A-36 steel and the bolts have diameter of 22 mm. Properties of 2L150 x 100 x 9.5 mm: A = 4660 mm2 t = 9.5 mm Fy = 248 MPa Fu = 400 MPa Properties of 20 mm A-325 bolts: Fu = 400 MPa 50 50 50 50 50 50,50 힝힝이어 Gusset Plate 9.5mm 100mm Gusset Plate 100mm 31.25 62.5 T 56.25 a. Nominal dimension of hole diameter, dn = 25 mm b. Determine the ultimate shear capacity (kN) of the connection. c. Determine the ultimate tearing capacity (kN) of the connection if the shear lag factor, U = 0.75.
The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If diameter of hole equals diameter of rivet, what is the net area of edge-1-3-4-edge in square millimeters? a. 2685.5 b. 2752.5 c. 2792.4 d. 2632.96 2. If diameter of hole equals diameter of rivet, what is the net area of edge-1-2-3-4-edge in square millimeters? a. 5325 b. 4685 c. 2890 d. 3080 3. What is the limiting value of the net area for this steel element with hole (square mm) a. 2880 b. 2646 c. 2856 d. 2080 4. If allowable rupture stress in holes is Fu/2 where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534.5 kN b. 560.5 kN c. 546.5 kN d. 550.5 kN
a] Compute LRFD 6.) Compute ASD CIVIL STEEL DESIGN ENGINEERING- BOLTED CONNECTION Sample Problem 5: The 175 x 100 x 16 mm angle shown connected to a gusset plate with three 25 mm bolts (A490) when threads are excluded from shear planes. The angle consists of A36 steel. Properties of 4 175 x 100 x 16 A36 Steel Properties of A490 bolts A = 4181 mm² t = 16 mm Fy = 248 MPa F₁ = 400 MPa Fy = 276 MPa Nominal hole dia. = 27 mm 75 T+ 100 Gusset Plate 100 F 100
A76 x 76 x6 mm angular section shown is welded to an 8 mm thick gusset plate. The length L1 is 65 mm, L2 is 125 mm, and the cross sectional area of the angle is 929 sq.mm. Fy-248MPA and Fu -400MPA. Gusset Plate Alowable Sresse Alowable tensle stress igross ara)0.00 Alowable tereile stres net area)0SOF. Allowable shear stress (net ares)0.30F. Determine the value of P based on net area using a strength reduction coefficient of 85% O 138.24 KN O 140.14 kN O 157.93 kN O 304.00 N Next
Question No.3: Determine the maximum tensile force, Pu, that can be applied to the connection shown in figure below based on the bolt strength; assume ASTM A36 steel for the following bolt types in standard holes: Check every limit state. a. 1-in.-diameter A325N, b. 7/8-in.-diameter A490X. 3" 3" 1½" /" plate ½P, P ½P. /" plate
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docs.google.com/forms/d/e/1FAlpQLSeFBz2FIWt2UFcalwXNpXsvWOZ8WZBIxcUHPJkK6-Zc Yes No O * The area of a steel bar with dimeter of 16 mm is 0.3115 square inch 0.175 square inch 200.96 square mm 113.04 square mm * Steel bars are made with different dimeters such as 6 mm 12 mm
7 GC32.p I x 106 notes 6 ASC b 06 notes 6 ASD GA Plate PL3/8"> G mccormac nels Facebook e.google.com/file/d/1Ry7imwGZ0HpuPvjaRolGNulyuu9bld19/view CENG324GC32 Principles of Design Sopen with utation Plate No. 7 Tension Member - Welded Connection Problem 1 A Plate PL3/8"x6" is welded to a gusset plate as shown in Figure 1. The A36 steel has a yield stress of Fy = 36 Ksi and an ultimate tensile stress Fu = 58 ksi. Assume Ae = Ag compute the allowable strength of the plate using Allowable Stress Design. PL x 6 Page 7 2 Pr へ
Fill in the blanks: A 300 x 12 mm plate is connected to 23mm diameter bolts arranged as shown, what is the capacity P = of the joint considering that no slippage will occur. The allowable stresses for friction type connections are 105 MPa for shear and 150 MPa for tension. 75mm 75mm 75mm 75mm 75 mm 300mm 15mm,
2-D flat plate.
Untitled Paint File View 69 X Clipboard ▷ 1224, 491px Q Search d 23 Image N V 607 x 634px 18° D 10 A 4 Tools Ⓒ d₂ d₁ PROB. 2.5-8 El 168 CHAPTER 2 Axially Loaded Members 2.5-8 A brass sleeve S is fitted over a steel bolt B (see figure), and the nut is tightened until it is just snug. The bolt has a diameter d = 25 mm, and the sleeve has inside and outside diameters d₁ = 26 mm and d₂ = 36 mm, respec- tively. dв Brushes Calculate the temperature rise AT that is required to produce a compressive stress of 25 MPa in the sleeve. (Use material properties as follows: for the sleeve, as = 21 X 10 °C and Es= 100 GPa; for the bolt, ag = 10 X 106/C and EB 200 GPa.) (Suggestion: Use the results of Example 2-8.) 1920 x 1080px N40 Sleeve (S) Shapes Bolt (B) 4+ M Size O OO 00 000 Colors 100% AVENG I 0 0% X + 11:33 CH 30/11/2022