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- Wood planks are used on each working level. The deck width/bearer span is 5 ft.. The bearers and posts are standard pipe and the pipe material is A36 steel with a yield stress of 36,000 psi and modulus of elasticity of 29,000,000 psi. Bearers are to be located at a vertical spacing of 10 ft (largest, lowest post height). Posts are to be 7 ft oc (plank length) parallel to the building wall and 5 ft apart (bearer length) perpendicular to the building wall. There are four working levels and the anticipated scaffold loading will be med duty. A. Assuming the ultimate bending strength of the planks is 3,800 psi (apply a 4:1 F.O.S.), determine the required minimum plank thickness to the nearest 100th. B. Based on the bearer material provided, what is the minimum pipe size that can be safely used? See Appendix 2 in your textbook for steel pipe properties. C. Based on the post material provided, can a 2” standard pipe be used safely? Be sure it satisfies buckling stress conditions only.A simply supported beam has a height of 600 mm and a width of 300mm. Determine the maximum safe live load that the beam can carry. The dead load is the beam weight plus a superimposed load of 15 kN/m The stirrup size is 12 mm, the top bars are 2-20 mm and the bottom bars are 5-28 mm. The clear distance between layers of bottom bars is the bar size, 28 mm. Use fc'=30 MPa, Grade 60 (fy=414 MPa) reinforcements and concrete cover of 50 mm.Problem 2: The loads on a roof beam consist of a dead load of 0.2R kN/m, a roof live load of0.13R kN/m, and a snow load of 0.14R kN/m. Apply allowable strength design approach todetermine the required load capacity (required strength) to be used in the design of thecolumn. Which AISC load combination controls? NOTE: use R=922
- ス F. reinforced concete structure is shown The floor framing plan oF in the figure. The beams are 280 mm wide and S20 mm deep, and the slob is 110mm thick an edditional (super impes) veight,1 and live lo ad of OTher than conerete weight, the floor subjected other to Is dead load of 3k Pa si2 k Por. Unit weight of concrete is 23.5 kN/m® le Determine the total uniform load on beam DEF and ABC axial load 20 Determme the total on columns A and B,D an) E 2Sm 티 2.Sm 6.2m 6.2mThe diagram shows a glulam beam. Douglas Fir from the 24F-1.7E is the member.(ASD only)Stress Level According to the sketch, the bending stress is located around the cross section's x axis.[D+0.75(S+ W)] are the loads. Utilise a single,C D based on the load with the shortest duration.in the synthesis Buckling is not a worry due to the bracing conditions. Take dry-service application (EMC 16%) into consideration. Temperature conditions are normal. Identify the adjusted ASD values below:positive design value for bending about the strong axis F negative design value for bending about the strong axis F Design for tension parallel to grain F_{t} ^ * F_{c} ^ * Design value for compression parallel to grain Under concentrated load, compression design value perpendicular to grain | F_e' on compression faceDesign with compression Design value for compression parallel to the grain at the support reactions tension face : F_{c} ^ * on When bending about the strong axis, shear design value…A3. A composite beam and deck system made up of W360x72 at 1000mm o.c. is to span 8m. The deck when cast is to be 100mm thick concrete (25MPA). The shear studs to be used have an ultimate stress capacity of 415MPA and will have a diameter of 16mm. Assuming 100% connection and that the system is shored during casting determine the ultimate moment of the composite W360.
- 3) Calculations Steel Structure Corridor Dead Load = (uniform load) Live Load = 80 psf (uniform load) Find Ac 15A cantilever timber beam with a span of L-3.7 m supports a uniformly distributed load w. The beam width is b- 320 mm and the beam height is h- 270 mm. The allowable bending stress of the wood is 5.7 MPa. Determine the magnitude of the maximum load w that may be carried by the beam. Answer: w- kN/m. Save for Later Attempts: 0 of 1 used Submit AnswerDesign data: fc'= 4.35 ksi fy = 60 ksi WOL-O2 p Dead Load: 0.82 kip/ft Live Load: 1.00 kip/ft Beam Spam Lenght = 14.5 t WL-1.00 ko Using: #9 bars for L.Reinforcement = As = 1.00 in2 # 3 bars for stirrups = As = 0.11 in2 Clear cover: 1.5 in Wu2.58 kip Load on load comb. Factored Load Wu 1.2 x DL+ 1.6 x LL Wu = 1.2 x 0.82 + 1.6 x 1.00 = 2.58 kip/ft Fig. 36 Beam Design
- 3.4 The required flexural (bending moment) strength is of a reinforced concrete beam is Mu = 260 kip-ft Determine which of the following reinforcing bar arrangements can be used for this beam. a) 6-#6 b) 4-#8 c) 3-#9 Material properties are: f'c = 5 ksi fy = 60 ksi 12" 24" #4 Stirrups 1in cover over the stirrupsProblem 1: Determine the allowable service live load, PL assume the dead load is due to the beam weight f'c = 3 ksi, fy = 60 ksi, Dc = 150 pcf. 25" 5" 4-#8 10" 10" PL 10" PL 10"Determine the maximum live load that the beam can carry if the beam depth is 600mm and beam width is 300mm. The dead load is 32 kN/m. The stirrup size is 12mm, the top bars are 2-20mm and the bottom bars are 5-32mm. The clear distance between layers of bottom bars is the bar size, 32mm. Use fc' = 28 MPa, Grade 60 reinforcements and concrete cover of 50mm. WDL = 32 kN/m (INCLUDING BEAM WEIGHT) WLL = ?? kN/m Wu kN/m 7.5m 600 od 300