Describe the mechanism by which benzene is converted to bromobenzene (C6H5Br) on treatment with a mixture of bromine and iron (III) bromide (Br2/FeBr3). Your answer should illustrate how the electrophile (Br*) is formed from the Br₂/FeBr3 and how it is involved in the electrophilic substitution of the aromatic ring.
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- Electrophilic aromatic substitution usually occurs at the 1-position of naphthalene, also called the a position. Predict the major products of the reactions of naphthalene with HNO3, H2SO4.Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H15l products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. наThe reaction of (S)-2-bromopentane with potassium cyanide to yield 2-methylpentanenitrile (2-cyanopentane) occurs due to a nucleophilic substitution pathway. The reaction is 100% stereospecific. Please explain what this observation tells about the mechanism of the reaction.
- The reaction of (S)-2-bromopentane with potassium cyanide to yield 2-methylpentanenitrile (2-cyanopentane) occurs via a nucleophilic substitution pathway. The reaction is 100% stereospecific.Predict the product formed in the nucleophilic aromatic substitution reaction between 1-chloro-2,4-dinitrobenzene and sodium methoxide (NaOCH3). Draw the mechanism for the reaction, showing why the product you have selected is formed.Treatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.
- Reaction of this bicycloalkene with bromine in carbon tetrachloride gives a trans dibro- mide. In both (a) and (b), the bromine atoms are trans to each other. However, only one of these products is formed. CH3 CH3 CH3 Br Br CH,Cl, + Br2 or Br Br (a) (b) Which trans dibromide is formed? How do you account for the fact that it is formed to the exclusion of the other trans dibromide?Nonconjugated , -unsaturated ketones, such as 3-cyclohexenone, are in an acid-catalyzed equilibrium with their conjugated , -unsaturated isomers. Propose a mechanism for this isomerization.Illustrate the resonance effect of the methoxy group -OCH3, on the structure of the benzene ring. Draw all the oissuvke resonance forms of methoxybenzene, including the hybrid Based on the structures, explain how the presence of the -OCH3 group affects: (i) the reactivity of the benzene ring towards electrophilic attack (ii) the orientation or point of attack of an incoming electrophilic reagent on the benzene ring.
- The reaction of (S)-2-bromopentane with potassium cyanide to yield 2-methylpentanenitrile (2-cyanopentane) occurs via a nucleophilic substitution pathway. The reaction is 100% stereospecific. Please explain in complete words what this observation tells you about the mechanism of the reaction.Compounds X and Y are both C,H15CI products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C-H14 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C-H151 products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. In (F ChemDoodleThe reaction of methylpropene with HBr, under radical conditions, gives two intermediates. Propose a mechanism for the formation of the two products. Propose a mechanism for the following reaction and use electronic factors to account for the formation of a major product: CH2 CH2Br N-Bromosuccinimide (NBS) ho, CCI4 Draw the structure of an antioxidant, Vitamin E free radical and use resonance structures o account for its stability.