Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H15l products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. на

Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C7H15l products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. на

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter10: Alcohols

Section: Chapter Questions

Problem 10.52P: Alcohols are important for organic synthesis, especially in situations involving alkenes. The...

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Compounds X and Y are both C,H15CI products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C-H14 alkene. Both X and Y undergo an SN2 reaction with sodium iodide in acetone solution to give C-H151 products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. In (F ChemDoodle
The electrophilic addition of HBr to 3-cyclohexylbut-1-ene gives a mixture of two constitutional isomers. These two isomers can also be produced from 3-cylcohexybut-2-ene, but one of which requires different reaction conditions; the electrophilic addition of HBr to 3-cylcohexybut-2-ene produces one of these isomers while the electrophilic addition of HBr to 3-cylcohexybut-2-ene, in the presence of peroxides, produces the other one. Draw the structure for the isomer product that can result from the reactants 3-cyclohexylbut-1-ene and 3-cylcohexybut-2-ene using different reaction conditions. Part 1 of 2 Click and drag to start drawing a structure. C 8 DY 000 8: >
Diphenylacetylene can be synthesized by the double dehydrohalogenation of 1,2-dibromo-1,2-diphenylethene. The sequence starting from (E)-1,2-diphenylethene consists of bromination to give the dibromide, followed by dehydrohalogenation to give a vinylic bromide, then a second dehydrohalogenation to give diphenylacetylene.(a) What is the structure, including stereochemistry, of the vinylic bromide?(b) If the sequence starts with (Z)-1,2-dibromo-1,2-diphenylethene, what is (are) the structure(s) of the intermediate dibromide(s)? What is the structure of the vinylic bromide?
Because bromocyclohexane is a secondary alkyl halide, both cyclohexanol and cyclohexene are formed when the alkyl halide reacts with hydroxide ion. Suggest a method to synthesize cyclohexanol from bromocyclohexane that forms little or no cyclohexene.
Compounds X has the formula C7H15Cl; Y is C7H15Br.X undergoes base-promoted E2 elimination to give a single alkene product Z. Y likewise reacts under similar conditions to give a single alkene product that is isomeric with ZCatalytic hydrogenation of Z affords 3-ethylpentane.X readily reacts in SN2 fashion with sodium iodide in acetone. Y does not undergo a similar SN2 reaction. Propose structures for X and Y.
When cyclohexene is reacted with hydrobromic acid in acetic acid, the major product is bromocyclohexane. There is a small amount of cyclohexyl acetate formed. What is the mechanism that forms both compounds? What is the purification procedure that isolates both compounds?
If phenoxide ion is allowed to react with 1-bromopentane, pentyl phenyl ether is obtained. However, if cyclohexane is used as the alkyl halide, the major products are phenol and cyclohexene. Explain how these products were formed.
Aldehydes and ketones undergo acid-catalyzed reaction with alcohols to yield hemiacetals, compounds that have one alcohol-like oxygen and one ether-like oxygen bonded to the same carbon. Further reaction of a hemiacetal with alcohol then yields an acetal, a compound that has two ether-like oxygens bonded to the same carbon. (a) Show the structures of the hemiacetal and acetal you would obtain by reaction of cyclohexanone with ethanol. (b) Propose a mechanism for the conversion of a hemiacetal into an acetal.
Bicyclo-2,5-heptadiene can be prepared in two steps from cyclopentadiene and vinyl chloride. Provide a mechanism for each step.
Alcohols are important for organic synthesis, especially in situations involving alkenes. The alcohol might be the desired product, or the OH group might be transformed into another functional group via halogenation, oxidation, or perhaps conversion to a sulfonic ester derivative. Formation of an alcohol from an alkene is particularly powerful because conditions can be chosen to produce either the Markovnikov or non-Markovnikov product from an unsymmetrical alkene. Using your reaction roadmap as a guide, show how to convert 4-methyl-1-pentene into 5-methylhexanenitrile. You must use 4-methyl-1-pentene and sodium cyanide as the source of all carbon atoms in the target molecule. Show all reagents needed and all molecules synthesized along the way.
Enamines normally react with methyl iodide to give two products: one arising from alkylation at nitrogen and the second arising from alkylation at carbon. For example, Heating the mixture of C-alkylation and N-alkylation products gives only the product from C-alkylation. Propose a mechanism for this isomerization.
Treatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.