Cystic fibrosis is an autosomal recessive genetic disorder. Which statement BEST explains how cystic fibrosis is maintained in the gene pool? O A. Organisms that are heterozygous can pass on only the dominant allele. O B. Organisms that are homozygous-dominant pass on either dominant or recessive alleles. O C. Organisms that are heterozygous can pass on the recessive alleles because they are carriers of the disorders but do not show characterisitcs of the disorder becuase they have the dominant allele as well. O D. Organisms that are homozygous-recessive pass on only the dominant allele.
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- 1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…Everyone in Merida's family has orange hair, which is the dominant trait for hair color in her kingdom. Her family brags that they are a "purebred" line. She recently married a man who has light yellow hair, which is a recessive trait. Create a Punnett square to show the possibilities that would result if they had children. Use H to represent the dominant gene and b to represent the recessive gene. List the possible genotypes and phenotypes for their children. What are the chances of a child with orange hair? What are the chances of a child with yellow hair? Would Merida's children still be considered purebreds? Explain!
- Define epistasis? a. Allelic variation at two different genes adds together in order to produce a phenotypic outcome b. Genetic variation and environmental variation both affect a given phenotype c. Allelic variation at one gene prevents or conceals the phenotypic consequences of allelic variation at a different gene d. Allelic variation at single gene affects many different phenotypes e. Genes that are near the start of a gene cluster are expressed before genes near the end of the clusterBiology When both parents are heterozygous carriers of the recessive allele that causes albinism, what percentage of their offspring will be heterozygous carriers of the albinism allele? Answer Choices: A: 25% B: 50% C: 75% D: 100%Cystic fibrosis is a genetic disease caused by a recessive allele. Two parents without the disease have a child with the disease, indicating they are both heterozygotes. Assuming that the child did not have a mutation giving it the disease, what is the probability that a second child of the same parents would have the disease? Group of answer choices a. 1 b. 0.25 c. 0 d. 0.5
- Using the information in the Punnett square that showing a cross between two parents, how would we refer to the parents and the offspring? a. One parent homozygous, one is heterozygous, the offspring are homozygous b. One parent is homozygous dominant, one parent is homozygous recessive, the offspring are heterozygous c. One parent is homozygous dominant , one parent is heterozygous recessive, the offspring are homozygous dominant d. One parent is heterozygous dominant, one is heterozygous recessive, the offspring are heterozygous dominant P generation: BB x bb Complete dominance: B = black rat b = white ratIn humans, the allele for colorblindness is found on the X chromosome and is recessive. If a woman is colorblind and her partner is not colorblind, what percent of their sons and/or daughters will be colorblind? A. 50% sons colorblind , 100% Daughters colorblind B. 0% sons colorblind , 100% Daughters colorblind C. 50% sons colorblind , 50% Daughters colorblind D. 100% sons colorblind, 0% Daughters colorblindWhat does a bell-shaped curve of a graph indicate? A. Mendelian inheritance pattern B. Incomplete dominance C. Codominance D. Continuous variation
- An animal has a genotype of two uppercase letters, such as AA. What is this type of genotype called? A. Homozygous Recessive O B. Homozygous Dominant C. Heterozygous Dominant O D. Heterozygous RecessiveWhat is Mendelian inheritance? a. Mendelian genes code an entire phenotype so that children will not be clones of their parents. b. Mendelian genetics are those genes that code for dominant or recessive illnesses but only if no polygenic traits cancel them out. c. Mendelian genes sit at one loci with one allele from Mom and one allele from Dad. d. Mendelian genetics is when two or more genes at two or more loci express one traitA is a dominant gene for normal pigment, and a is its recessive allele for albinism (and pink eyes). B is a dominant gene for brown eyes, and b is its recessive allele (blue). What is the mother's genotype if two brown-eyed parents have fraternal twins, one with blue eyes and one with pink eyes (albino)? a. AaBb b. AaBB c. aaBb d. aabb e. AABB