Construct the requested confidence interval. A survey of 400 non-fatal accidents revealed that 268 involved a distracted driver using some kind of electronic device. Construct a 95% confidence interval for the proportion of non-fatal accidents involving a distracted driver using some kind of electronic device.

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: A research center survey of 2,384 adults found that 1,868 had bought something online. Of these…

A: From the provided information,Sample size (n) = 2384From which 1247 are weekly online…

Q: Thirteen out of the 137 randomly selected faculty members who were surveyed at a community college…

A: Obtain the 90% confidence interval for the proportion of all faculty member at the community college…

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: In a survey, 150 people were asked to identify their main source of news information; 93 indicated…

A: Given: The sample number of people that were asked to identify their main source of news information…

Q: In a survey of 3478 adults, 1462 say they have started paying bills online in the last year.…

A: From the provided information,Confidence level = 99%

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: In a survey of 3985 ​adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Solution

Q: A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the 1227 males​…

A:

Q: 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a…

A:

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: In a study of accuracy of fast food drive throughs.  McDonalds had 27 orders that were not accurate…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: 1000 randomly selected Americans were asked if they believed the minimum wage should be raised. 600…

A: Givensample size(n)=1000x=600sample proportion(p^)=xn=6001000=0.6confidence level=95%

Q: n a randomly selected group of 750 automobile deaths, 240 were alcohol related. Construct a 95%…

A: Given that,  x = 240, n = 750 The value of sample proportion is,

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: A sample of 421 adults showed that 239 of them are connected to the Internet from home.  Construct…

A: From the provided information, Sample size (n) = 421 From which 239 are connected to the Internet…

Q: In a random sample of 575 American goods, about 46.3% of them were transported by rail in 2017.…

A: Given,   Sample size = 575 Sample proportion = 0.463   Critical value: Using z-table, the z-critical…

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: In a randomly selected group of 650 automobile deaths, 180 were alcohol-related. Construct a 95%…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: Of 346 items tested, 22 are found to be defective. Construct the 98% confidence interval for the…

A: Solution: Let X be the number of items found to be defective and n be the sample number of items…

Q: In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: Insurance companies are interested in knowing the popul drivers who always buckle up before riding…

A: Given data,No of people surveyed n=387who claims to buckle up is x=311Construct a 93 % CI?

Q: A sanatorium conducted a study on 3,500 women over 35 years of age, of whom 220 reported having…

A: Step 1: State the given data: number of favorable cases, x = 220sample size, n = 3500confidence…

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: 700 randomly selected Americans were asked if they believed the minimum wage should be raised. 350…

A: Given that  p = 700 x = 350 Confidence level(c) = 90% = 0.90 Significance level (α) = 1-c = 1-0.90=…

Q: In a college 500 students were randomly selected for a survey to determine if they own a laptop. Of…

A: X: No. of students who own a laptop. Given:

Q: In a random sample of 230 men , 18 or older , 142 were married. Construct and explain a 90%…

A: Solution: Let X be the number of married men 18 or older and n be the sample number of men. From the…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.