In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results.

Q: In a survey of 2591 adults in a recent​ year 1414, say they have made a New​ Year's resolution.…

A: From the provided information,Confidence level = 90% and 95%

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

A:

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: According to a recent survey of 1600 people, 62 % feel that the president is doing an acceptable…

A: Obtain the 90% confidence interval for the population proportion of people who feel the president is…

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A:

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: Define the confidence level?

A: It is the likelihood of containing the true population parameter under the confidence interval when…

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Out of 180 randomly selected adults in the United States who were surveyed, 81 exercise on a regular…

A:

Q: In a survey of 793 adults, 460 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 793 X = 460 98% confidence interval,

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: In a sample of 310 adults, 177 had children. Construct a 87% confidence interval for the true…

A: Find z-critical value:…

Q: aOf 500 random people surveyed, 72 were smokers. Find the 80% confidence interval for smokers.

A: It is given that, Out of 500 random people surveyed, 72 were smokers. So, the portion of the…

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: In a survey of 2782 adults, 1411 say they have started paying bills online in the last year.…

A:

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: In a random sample of 230 men , 18 or older , 142 were married. Construct and explain a 90%…

A: Solution: Let X be the number of married men 18 or older and n be the sample number of men. From the…

Q: Out of 42738 freshmen entering the State University system,  27298 of them need to take remedial…

A:

Q: Katy Perry is currently the most popular account on Twitter® with about 100 million followers. Mrs.…

A: Given  X=308, n=500, alpha=0.05 90% CI for population proportion

Q: In a random sample of 230 men, 18 or older, 142 are married. Construct and explain a 98% confidence…

A: Given Data Sample Size, n = 230 Number of successes, x = 142.0 Significance level,…

Q: In a survey of 2947 ​adults, 1430 say they have started paying bills online in the last year.…

A: X = 1430 N = 2947 99% confidence level

Q: In a survey of 1219 U.S. adults, 354 said that their favorite sport to watch is football. Construct…

A: According to the given information, we have Total number of U.S. adults = 1219 354 said that their…

Q: In a survey of 2567 ​adults, 1431 say they have started paying bills online in the last year.…

A: The objective of this question is to construct a 99% confidence interval for the population…

Q: One year’s survey results, of 1525 respondents, 846 said that they expected difficulty finding a…

A:

Q: In a survey of 2569 adults in a recent​ year, 1303 say they have made a New​ Year's resolution.…

A: Given data  n= 2569 X = 1303