Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- For the following problem: Identify the gametes for each parent, build a Punnett Square of the probability of offspring. Show the resulting genotype ratios and the resulting phenotype ratios. The submission file on Canvas will typically have a multiple-choice component or may be a fill-in-the-blank question related to genotype and/or phenotype outcomes. Be prepared to address all of these details in the questions. In mice, brown fur (B) is dominant over gray fur (b). Show the probable outcomes of a gray mouse bred with a homozygous dominant mouse. b) If two of this F1 generation had offspring is there any chance of there being a mouse with recessive coloration?arrow_forwardAn individual heterozygous for d e f (D/d E/e F/f) was crossed to a homozygous recessive individual (d/d e/e f/f). The following offspring were recovered.d e + 39+ e f 372d + f 7+ + f 47+ e + 5d + + 412What is the correct order of these genes? EDF DFE DEFarrow_forwardDrosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results: in the image Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.arrow_forward
- Deduce the phenotypic proportions in the progeny of thefollowing crosses of autotetraploids in which the a+/a locus is very close to the centromere. (Assume that the fourhomologous chromosomes of any one type pair randomly two by two and that only one copy of the a+ allele isnecessary for the wild-type phenotype.)a. a+/a+/a/a × a/a/a /ab. a+/a/a /a × a/a/a/ac. a+/a/a /a × a+/a/a /ad. a+/a+/a /a × a+/a/a /aarrow_forward. In a dihybrid test cross, the following results were obtained: A‑B‑, 121; A‑bb, 107; aaB-, 115; and aabb, 93. Do these data approximate a dihybrid test cross ratio with independent assortment? Complete the following table and answer the related questions. Phenotype O E (O-E) (O-E)2 (O-E)2/E A_B_ 121 A_bb 107 aaB_ 115 aabb 93 Totals X2= Instructor’s Calculation of X2= 4.0367 In interpreting this X2 value, you have ____3_______degrees of freedom. In this case do you accept/reject the hypothesis that these data approximate a dihybrid test cross ratio with independent assortment? What is the probability that the deviations are due to chance alone?arrow_forwardTomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Determine the recombination frequency between the genes for fruit colour and fruit shape using the following formula (in picture). Show your work. Record your answer as a whole number percentage.arrow_forward
- Tired of watering her garden, your instructor is attempting to grow desert plants. One such plant is Indian Paintbrush. A yellow variant has shown up, and we would like to determine if this variant segregates as a single-locus, Mendelian trait. We have taken a pure breeding red plant and crossed it with a pure breeding yellow plant. The resulting F1 plants were self-pollinated with the following results: Red Flowers 158 Yellow Flowers 92 Perform a chi square analysis on this data using the following hypothesis: The mode of inheritance for flower color in Indian Paintbrush is simple Mendelian. Calculate the chi square value without rounding and then round your final answer to three decimal places and put it in the space provided. Answer:arrow_forwardIn cucumbers, speckled fruit color (u') is dominant to uniform fruit color (u), and large spines (ss") are dominant to small spines (ss). These two genes are linked at a map distance of 20.4 m.u. A true-breeding cucumber plant with speckled fruit and large spines is crossed with a true-breeding plant with uniform fruit color and small spines. One of the F1 plants is crossed with a plant with uniform fruit color and small spines. What percentage of the offspring of this cross are expected to have uniform fruit color and small spines? 39.8% 10.2% 79.6% 20.4%arrow_forwardConsider the cross between a male with genotype AaBbCc and a female with genotype AaBBcc, where A is dominant to a; B is dominant to b; C is dominant to c. All loci assort independently. What is the probability that progeny will be aaBBcc or AaBbCc? Use two decimal places for your answer. If your answer is less than 1, lift a O in the ones place. For example, if your calculated answer is 0.9781, you should enter 0.98.arrow_forward
- Below is the linkage map for genes y, sh and c that are in cis arrangement. Interference is 0.4 and the total progeny is 2000. Determine the parentals, SCOI, SCO II, and DCO products and the estimated number of individuals for each. y-------------sh-- 18% 28%arrow_forwardShort hair (S) in rabbits is dominant over long hair (s). The following crosses are carried out, producing the progeny shown. Give all possible genotypes of the parents in each cross.arrow_forwardIn a cross between pure-breeding tall plants with pure-breeding short plants performed by Mendel, all of the F1 are tall. When these plants are allowed to fertilize themselves, the F2 plants occur in a ratio of 3 tall to 1 short. Which of the following is NOT a valid conclusion from these results? O A. The allele that produces the tall condition is dominant to the allele that produces the short condition. O B. The difference between tall and short stature in these lines is controlled by a single gene pair. O C. Fertilization occurs randomly between gametes carrying the tall and short alleles. D. The tall and short traits assort independently of each other in this cross. E. During production of gametes in F1 plants, the tall and short alleles segregate from each other equally into the gametes. Reset Selection VMark for Review What's This?arrow_forward
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