Consider a cross between a true breeding purple flowered pea plant (genotype PP) and a true breeding white flowered pea plant (genotype pp) that produces all heterozygous F1 offspring. An F1 intercross is conducted between two of the F1 offspring, resulting in the F2 generation. What is the expected phenotype outcome of the F2 individuals resulting from the F1 intercross?
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- Consider a cross between a true breeding purple flowered pea plant (genotype PP) and a true breeding white flowered pea plant (genotype pp) that produces all heterozygous F1 offspring. An F1 intercross is conducted between two of the F1 offspring, resulting in the F2 generation. What is the expected genotpye outcome of the F2 individuals resulting from the F1 intercross? 1PP: 2Pp: 1pp 1PP: 1Рp: 1pp 100% Pp 1PP: 1pp 100% ppSummer squash exist in long, spherical, or disk shapes. When atrue-breeding long-shaped strain was crossed to a true-breedingdisk-shaped strain, all of the F1 offspring were disk-shaped. Whenthe F1 offspring were allowed to self-fertilize, the F2 generationconsisted of a ratio of 9 disk-shaped to 6 round-shaped to 1 longshaped. Assuming the shape of summer squash is governed by twodifferent genes, with each gene existing in two alleles, propose amechanism to account for this 9:6:1 ratioTwo genes of a flower, one controlling blue (B) versus white(b) petals and the other controlling round (R) versus oval (r)stamens, are linked and are 10 map units apart. You cross ahomozygous blue oval plant with a homozygous white round plant. The resulting F1 progeny are crossed with homozygouswhite oval plants, and 1,000 offspring plants are obtained.How many plants of each of the four phenotypes do youexpect?
- In autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. Each of the F1 GGgg plants would obtain 12 gametes which are 2GG, 8Gg, and 2g. How were these obtained?A trait in garden peas involves the curling of leaves. A two-factorcross was made by crossing a plant with yellow pods and curlingleaves to a wild-type plant with green pods and normal leaves. AllF1 offspring had green pods and normal leaves. The F1 plants werethen crossed to plants with yellow pods and curling leaves. Thefollowing results were obtained: 117 green pods, normal leaves115 yellow pods, curling leaves78 green pods, curling leaves80 yellow pods, normal leavesA. Conduct a chi square analysis to determine if these two genesare linked.B. If they are linked, calculate the map distance between the twogenes. How accurate do you think this calculated distance is?How can you tell whether or not there are blue kernels? The Y was dominant. Set up and complete a Punnett square for a cross of two of the F1 from Step 1 (above). Answer these questions: What are the genotypes of the F2 generation? YY, Yy, yy What are their phenotypes? YY, Yy(yellow) , yy(blue) Are there more or fewer blue kernels than in the F1 generation? F2 generation has more blue kernels than F1. Identify the four possible gametes produced by the following individuals (Y = yellow, y = blue, S = smooth, s = wrinkled): YY Ss: YS Ys YS Ys Yy Ss: YS Ys yS ys Create a Punnett square using these gametes as P1 and determine the genotypes of the F1. YS Ys YS YYSS YYSs Ys YYSs YYss yS YySS YySs ys YySs Yyss What are the phenotypes? What is the ratio of those phenotypes? The phenotypes would be: (a) Yellow with smooth (b) Yellow with wrinkled 3:1…
- type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64Mendelian ratios are modified in crosses involving autotetraploids.Assume that one plant expresses the dominant trait greenseeds and is homozygous (WWWW). This plant is crossed to onewith white seeds that is also homozygous (wwww). If only onedominant allele is sufficient to produce green seeds, predict theF1 and F2 results of such a cross. Assume that synapsis betweenchromosome pairs is random during meiosis.
- A cross was made between a Red and Long flowered (RRLL) plant and a blue and dwarfflowered (rrll) plant. The resulting F1 plants were testcrossed to blue and dwarf plants.160 red and long40 red and dwarf38 blue and long150 blue and dwarfAfter showing your Punnett square for the testcross, use the Chi Square test to determine if thegenes are assorting independently. If they are linked, calculate the distance between the twogenes. Show your work.A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >In a diploid plant species, an F1 with the genotype Gg Ll Tt is test-crossed to a pure-breeding recessive plant with the genotype gg ll tt. The offspring genotypes are listed in the table. Genotype Number Gg Ll Tt 621 Gg Ll tt 3 Gg ll Tt 64 Gg ll tt 109 gg Ll Tt 103 gg Ll tt 67 gg ll Tt 7 gg ll tt 626 1600 Calculate the recombination frequency between G and T pair of genes. A. 0.227 B. 0.139 C. 0.454 D. 0.233