Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Wild-type mice have brown fur and short tails. Loss of function of a particular gene produces white fur, while loss of function of another gene produces long tails, and loss of function at a third locus produces agitated behavior. Each of these loss of function alleles is recessive. If a wild-type mouse is crossed with a triple mutant, and their F1 progeny is test-crossed, the following recombination frequencies are observed among their progeny. Produce a genetic map for these loci. Brown, short tailed, normal: 955 White, short tailed, normal: 16 Brown, short tailed, agitated: 0 White, short tailed, agitated: 36 Brown, long tailed, normal: White, long tailed, normal: Brown, long tailed, agitated: 46 0 14 White, long tailed, agitated: 933arrow_forwardContinuing his experiments, in Miles Morales' genome, the Goblin found similar genes, including one for invisibility which also seems to be dominant. To determine if they were linked to agility, the Goblin set up another cross and got the following results: Phenotype Agility and Invisibility Agility Invisibility No Powers Number of Progeny 121 52 55 125 What is the chi-square value for this?arrow_forwardIn a true breeding parental cross for an Autosomal recessive disease trait, the expected proportion of males in the F2 generation that are unaffected is:arrow_forward
- Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of each offspring with the following genotypes: (Note: 4 alleles – red; 3 – medium red; 2 – intermediate red; 1 – light red; 0 – white). CAPITAL letters only and with spaces when applicable. AABb - AaBb - AABB - aaBb - aabb -arrow_forwardLocus A has two alleles (A and a) while locus B has two alleles (B and b). The recombination frequency between locus A and locus B is 17%. A F1 heterozygote in trans-configuration is mated with an aabb individual. What are the expected phenotypic percentages in the resulting progeny? Round your percentages to the nearest tenths and in the following format, replacing the "0.0" with your percentages:arrow_forwardIn a parental cross of a autosomal dominant homozygous lethal disease trait, where the father is affected and mother unaffected, 50% of offspring will have disease phenotype and 50% will have the wild type phenotype. In f1 cross between affected male and unaffected female, the expected proportions of the disease phenotype and the wild type phenotype in the f2 generation are:arrow_forward
- The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…arrow_forwardDr. Thompson learned in her university genetics course to memorize probability outcomes from monohybrid crossing scenarios so there is never a need for drawing Punnett squares or forked line diagrams. Which equation would Dr. Thompson use to predict the probability of obtaining a tester outcome from the cross of MmNn X Mmnn? a) ¼ mm X ½ nn. b) ½ mm X ½ nn. c) ½ Mm X ½ nn. d) ½ Mm X ¼ nn.arrow_forwardWhat cross will result in a ratio of 3 dominant phenotype offspring for every 1 recessive offspring? What cross will result in a 1:2:1 genotype ratio in the offspring? What cross will result in all homozygous recessive offspring?arrow_forward
- As a graduate student, you join a lab and you are looking through some old notebooks. You find a linkage map someone has drawn. G--15 mu-----T----10 mu-------B If you plan to complete a test cross with a GtB/gTb male, A) What are all of the expected progeny genotypes? B.) How many of each genotype would you expect if you collected 1000 progeny?arrow_forwardIn the rat, the pattern of coat color is affected by a gene with two alleles. PH is the allele for hooded, in which the animal is mostly white with color restricted to the shoulders and neck. P+ is the normal solid body color allele. These two alleles exhibit incomplete dominance, so that heterozygotes have white bellies only. A true-breeding solid strain is crossed with a true-breeding hooded strain, to produce an F₁ generation that is all white belly. The F₁ generation rats are mated with each other to produce 800 F₂ offspring. Below is a table that gives the observed number of each phenotype in the F2 and also gives you the expected number. Question: If you perform a Chi-square goodness of fit test, what is the value of Chi square X² (Express your answer to the hundredths.) solid white belly hooded Σ Observed 195 420 185 800 Expected 200 400 200 800arrow_forwardO All three genes are linked, but need to do more crosses and data to determine the gene order. All three genes are linked with the flower color gene (F) in the middle. All three genes are linked with the seed weight gene (S) in the middle. All three genes are linked with the leaf size gene (L) in the middle.arrow_forward
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