Consider these reactions: Reaction 1: H₂(g) + Cl₂(g) → 2HCl(g) Reaction 2: 20F2 (g) → O₂(g) + 2 F₂ (g) Reaction 3: N₂(g) +202 (9) → 2NO₂ (g) Use Reaction 2. Answer: - AH = -184.6 kJ AH-49.4 kJ kJ AH +66.4 kJ How much energy (in kJ) is released when 81.0 g of oxygen difluoride decomposes? Enter a positive number. Round to the nearest hundredth. =

Given the reactions, X(s) + 1/2O₂(g) XCO₂ (s) XO(s) XO(s) + CO₂(g) what is AH for this reaction? X(s) + 1/2O₂(g) + CO₂(g) AH = -763.1 kJ AH = +159.3 kJ XCO3(s)

Calculate the value of AH for the following reaction: 2 NO₂ (g) N₂O4 (g) → based on the formation reactions for each of the reaction components as shown below: N2 (g) + O2(g) →→→ NO₂ (g) AH = 33.2 kJ/mol N₂ (g) + 2O2 (g) →→→ N₂O4 (g) AH₂ = 11.1 kJ/mol AH: kJ/mol

Consider these reactions: Reaction 1: H2(g) + Cl2(g) 2HCI(g) AH = -184.6 kJ Reaction 2: 20F2(g)- O2(g) + 2 F2(g) AH = -49.4 kJ Reaction 3: N2(g) + 202(g) 2NO2(g) AH = +66.4 kJ Reaction 2 can be described as an [Select] [ Select ] reaction

Given the following reactions: N2 (g) + O2 (g) → 2NO (g) AH = +180.7 kJ 2N20 (g) → O2 (g) + 2N2 (g) AH = -163.2 kJ the enthalpy of reaction for 2N20 (g) → 2NOo (g) + N2 (g) is kJ. -343.9 343.9 -145.7 145.7 O 17.5

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TUMU Consider these reactions: Reaction 1: H₂(g) + Cl₂(g) → 2HCl(g) AH = -184.6 kJ Reaction 2: 20F 2(g) → O₂(g) + 2 F₂ (g) Reaction 3: N₂(g) +202(g) →→→ 2NO₂(g) Use Reaction 1. Answer: AH = -49.4 kJ Determine the mass, in grams, of chlorine gas consumed (with excess H₂) when 1,152.0 kJ of energy is released from the system. Round to the nearest whole number. g AH = +66.4 kJ

Calculate AH for the following reaction, given the data in the table below: 4N204 (2) →2N20g) + 4NO2 (g) + 302 AH = ??? kJ/mol 2NO2 (e) + 2NO() +O2 (g)→2N2O4 (g) AH = -396.81 kJ 4NO+ 2N2Og) + 502 (g)→4N2O4 (g) AH = -398.88 kJ 2NO + O2 ()→N2O4 (3) AH = -173.09 kJ