1. What is 4,H for this reaction: 3C(s) + 4H2(g) → C3H8(g) given the following reactions: C3H8(g) +502(g) → 3CO2(g) + 4H2O(g) C(s) + O2(g) → CO₂(g) 4-H = -2043 kJ/mol 4,H=-393.5 kJ/mol 4,H= -483.6 kJ/mol 2H₂(g) + O₂(g) → 2H₂O(g) (a) -4191 kJ/mol (b) 1166 kJ/mol (c) 378 kJ/mol (d) -105 kJ/mol

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1. What is 4-H for this reaction: 3C(s) + 4H2(g) → C3H8(g) given the following reactions:
C3H8(g) +502(g) → 3CO2(g) + 4H2O(g)
C(s) + O2(g) → CO2(g)
4-H = -2043 kJ/mol
AH = -393.5 kJ/mol
4,H= -483.6 kJ/mol
2H₂(g) + O2(g) → 2H₂O(g)
(a) -4191 kJ/mol
(b) 1166 kJ/mol
(c) 378 kJ/mol
(d) -105 kJ/mol
Transcribed Image Text:1. What is 4-H for this reaction: 3C(s) + 4H2(g) → C3H8(g) given the following reactions: C3H8(g) +502(g) → 3CO2(g) + 4H2O(g) C(s) + O2(g) → CO2(g) 4-H = -2043 kJ/mol AH = -393.5 kJ/mol 4,H= -483.6 kJ/mol 2H₂(g) + O2(g) → 2H₂O(g) (a) -4191 kJ/mol (b) 1166 kJ/mol (c) 378 kJ/mol (d) -105 kJ/mol
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The enthalpy change is a state function and the Hess law states that the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states.

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