Consider a phospholipid vesicle containing 13.0 mM Nat ions. The vesicle is bathed in a solution that contains 50.0 mM Nations, and the electrical potential difference across the vesicle membrane AW= outside inside =-30 mV. inside-30 What is the electrochemical potential at 25.0 °C for Nations? (Faraday's constant=96.49 kJ/V mol.)
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- A cell contains 100 mM K+ and is surrounded by interstitial fluid containing 10 mM K+. The equilibrium potential for potassium is -58mV. What is the temperature of the cell, in degrees C? Enter your answer as a whole number. Do not use words or symbols.The distribution of Na* ions across a typical biological membrane is 10 mmol/dm3 inside the cell, and 140 mmol/dm³ outside the cell. At equilibrium, the concentrations across the membrane are equal. What is the Gibbs energy difference across the membrane at 37°C? The stated difference in concentration MUST be maintained by coupling to reactions that have at least your calculated difference of Gibbs energy. Ans: 6.8 kJ/molA galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: 2+ 2+ Sn(aq) +Ba(s) → Sn (s) + Ba** (aq) 2+ 2+ Suppose the cell is prepared with 7.71 M Sn in one half-cell and 5.89 MBa in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.
- What is the value for the w (water potential) of a cell when placed in a hypertonic saline solution of 0.40 M under standard atmospheric pressure (1.0 MPa) and at a room temperature of 25° C? [Assume that the cell and solution , (solute potential) are at equilibrium. Use 0.08314L bar K mol as the gas constant (R)]Calculate the free energy required to move 1 mol of K* ions from inside the cell (where concentration of K+= 0.063 M) to the outside the cell (where concentration K+= 0.17 M). The membrane potential is -0.05 V and the temperature is 303.06 K. K+ (inside cell) → K* (outside cell)Estimate the osmotic pressure of a solution of 0.1 M NaCl at 25°C. Assume 100% ionization of solute.
- Zinc-air batteries are actively being researched because one reactant (oxygen) is provided in infinite supply for free. The standard cell potential for this battery is 1.65 V. If the cell potential is 1.61 V, what is the partial pressure of oxygen in the cell and a temperature is 25.0\deg C? The reaction in the cell converts Zn(s) and O2(g) into ZnO(s). 2Zn(s) 02 (g) -> 2ZnO(s)A beaker contains two compartments (A and B) with equal volumes of solution separated by an artificial membrane with a pore size of 24 Angstrom (Å). Explain the net movement of solute if Compartment A has 3% albumin while compartment B has 2% potato starch (albumin diameter = 38 Å; potato starch = 300,000-1000000 Å).The simple form of |Hoff equation is: II = [B]RT In this equation the [B] is the molar concentration of solute. So: n m [B] = v MV = cg /MA Where c, the mass concentration of the solute is in the total volume of solution and M, is the molar mass of the solute. This equation can be replaced in the previous one to get: RT II = MA In this equation molar mass of given solute can be detemined from the slope of the II vs Cz plot. This equation applies only to solutions that are sufficiently dilute to behave as ideal-dilute solutions. In the case of non-ideal solutions, however, the extended formula is: II = [B]RT{1+ k. [B] + n. [B]² + ...} Biological macromolecules dissolve to produce solutions that are far from ideal, but we can still calculate the osmotic pressure by assuming that the van't Hoff equation is only the first term of a lengthier expression: II [B]RT(1+ b. [B]) II = RT + bRT. [B] [B] II = RT + bRT./M. */Ma п RT ÞRT Ca MA MA In this equation molar mass of given biomolecule can…
- what is the property of the solution that makes log(concentration) Vs electrochemical potential deviates from linear line at high concentrations?Use the equation of your line to calculate an accurate concentration of solute if the absorbance is 0.15 AU. Show your calculations.At Electrochemical Equilibrium, which best describes the distribution of ions in the chamber, on either side of the membrane, when one "mole" of salt (NaCl) is added to one side of a 1 liter chamber, filled with water and divided in half by a membrane permeable only to Na+. 2.0 M CI- and 1.25 M Na+ one side of the membrane; 0.75 M Na+ on the other side of the membrane. 1.0 M CI- and 1.0 M Na+ on both sides of the membrane. 2.0 M CI- and 1.0 M Na+ one side of the membrane; 1.0 M Na+ on the other side of the membrane. 2.0 M CI- and 2.0 M Na+ on one side of the membrane; pure water on the other side of the membrane.