Consider a pencil-shaped protein with two epitopes, Y (the “eraser” end) and Z (the “point” end). They are recognized by antibodies A1 and A2, respectively. Draw and label a picture showing the antibodies linking proteins into a complex that could trigger endocytosis by a macrophage.
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Consider a pencil-shaped protein with two epitopes, Y (the “eraser” end) and Z (the “point” end). They are recognized by antibodies A1 and A2, respectively. Draw and label a picture showing the antibodies linking proteins into a complex that could trigger endocytosis by a macrophage.
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- Write T if the statement is correct; write F if the statement is not correct. P and E selectins are expressed by endothelial cells. " " TCRs consist of heavy and light chains. " " A disulfide bond can be found on TCRs. " " The antigen binding site in TCRs is contributed by the variable region of the H chain and the variable region of the light chain. " " CD4, but not CD8, interacts with Lck. " "Draw a schematic diagram of a typical IgG molecule and label each of the following parts: H chains, L chains, intrachain disulfide bonds, hinge, Fab, Fc, and all the domains. Indicate which domains are involved in antigen binding.How are antibodies unique? Please discuss the structure of an antibody. What are the V and C regions? Discuss how the few hundred genes involved are capable of making endless amounts of antibodies. Besides medical treatment what is another way antibodies can be used?
- For the diagram below, all of the following statements are true EXCEPT: Antigen- binding site V C Heavy chain V Light chain S.S. Fc (stem) region c C Hinge region None of the other four answers (All are true statements) Antibodies (Immunoglobulins) are composed of four protein molecules, two identical "light" chains and two identical "heavy" chains Antigens bind to the "stem", composed of the constant regions of the two "heavy" chains The variable (V) regions form the antigen binding sites The constant (C) regions determine class of antibodyThere are five major classes of antibodies. Complete the two below.Illustrate the structure of an antibody molecule. Label the constant and variable regions, the Fc and Fab parts, and the heavy and light chains.
- Construct a typical antibody (immunoglobulin) molecule. Label the variable and constant regions, and the light and heavy chains. Indicate which region determines the antibody’s isotype (class). Indicate which region determines its antigenic specificity.Draw the structure of an antibody molecule(a typical IgG)and show how this structure enables it to bind to a specific antigen. Include the following terms in your diagranm: heavy chain (H chain), light chain (L chain), variable region, constant region, Fab, Fc, hinge and disulfide bonds.There are five major classes of antibodies. Complete the three below.
- Which antibody type description among A- D is falsely characterized? A) O IgA: form dimers; prevent adherence of pathogens to mucosal surfaces 1f1 B) O IgG: circulating antibody with multiple functions; formed in high numbers in secondary antibody response C) O IgM: forms multimers whose function is agglutination of infectious microbes D) O IgE, IgD: carry out their function while bound to the surfaces of specific cell types E) O None are false, A-D are all correctAddition of immunoglobulin G (IgG) specific for hemoglobin to a solution of hemoglobin results in the formation of a red precipitate. In contrast, addition of the Fab fragments from this antibody to hemoglobin results in no such precipitate. What could explain this difference in results? Treatment with papain produces Fab fragments with different antigen specificity than the original IgG molecule. IgG can simultaneously bind two different antigens, whereas an Fab fragment can only bind one antigen at a time. The Fab fragments preferentially bind to other Fab fragments rather than to hemoglobin. The hemoglobin molecule antibody-binding sites can bind IgG molecules, but cannot bind Fab fragments.Match the antibody in Column A with its description or function in Column B. There may be more than one answer for each antibody.