COMPLETE THIS CODE and make sure it passes all the test cases. // EXERCISE 4.1 MYLIST ITERATIVE CATENATE MUTATE /**  * Catenate two MyLists, listA and listB. Mutate listA.  * @param listA is a MyList object.  * @param listB is a MyList object.  * @return a list consisting of the elements of listA followed by the  * elements of listB.  */ public static MyList iterCatMutList(MyList listA, MyList listB) {                }

starter code //Provided imports, feel free to use these if neededimport java.util.Collections;import java.util.ArrayList; /** * TODO: add class header */public class Sorts {    /**     * this helper finds the appropriate number of buckets you should allocate     * based on the range of the values in the input list     * @param list the input list to bucket sort     * @return number of buckets     */    private static int assignNumBuckets(ArrayList<Integer> list) {        Integer max = Collections.max(list);        Integer min = Collections.min(list);        return (int) Math.sqrt(max - min) + 1;    }     /**     * this helper finds the appropriate bucket index that a data should be     * placed in     * @param data a particular data from the input list if you are using     *             loop iteration     * @param numBuckets number of buckets     * @param listMin the smallest element of the input list     * @return the index of the bucket for which the particular data should…

Set and Map class templates are similar in the sense that they both use binary search trees. The difference is Set is used to store only keys while Map is used to store (key, value) pairs.  Group of answer choices True False

Lab 14.1 Beginning to build an Arrazlizt recursively In this sequence of problems we practice recursion by abandoning our reliance on iteration. We resolve to solve a sequence of problems without using while or for loops. Instead we will think recursively and look at the world through a different lens. Recursion is all about solving a large problem by using the solution to a similar smaller problem. The brilliant thing about recursion is that you can assume you already know how to solve the smaller problem. The goal is to demonstrate how the smaller solution relates to the larger problem at hand. For example, suppose you want to print all binary strings of length 3 and you already know how to print all binary strings of length 2. Here they are: 00 01 10 11 How can we solve the larger problem with a list of strings of length 2? Add a "0" or "1", right? So here is the solution to the larger problem: 00 + 0 = 000 01 + 0 = 010 10 + 0 = 100 11 +0 = 110 and 00 + 1 = 001 01 + 1 = 011 10 + 1 =…