Calculate the Arzn Hofor the reaction 2 Fe(s) + O₂(g) → Fe₂O3(s) using the reactions below. 1 Fe(s) + 3 H₂O(1)→ Fe(OH)3 (8) + H₂(g) Am H = +161 kJ/mol Arn H=-286 kJ/mol 2 H₂(g) + O2 → H₂O(1) 3 Fe₂O3(s) + 3 H₂O(l) → 2 Fe(OH)3 (8) Ar H=+289 kJ/mol Which of the statements below are false for the calculation? I. Reaction 1 must be multiplied by 2 to give 2 Fe(s) + 6 H₂O(1)→2 Fe(OH)3(s) + 3 H₂(g), Arz H=+322 kJ/mol. II. Reaction 1 must be divided by 3 to give Fe(s) + H₂O(1)→ Fe(OH),(s) + H₂(9), Aram H = +53.67 kJ/mol. III. Reaction 2 must be multiplied by 3 to give 3 H₂(g) + O₂ + 3 H₂O(1), AH = -858 kJ/mol. IV. Reaction 3 must be reversed to give 2 Fe(OH)3 (8)→ Fe₂O3(s) + 3 H₂O(1), AH = 289 kJ/mol. V. The Aran Hº for 2 Fe(s) + O₂(g) → Fe₂O₂ (s) is 825 kJ/mol. II, IV, and V I and IV II and IV II, III, and V I, III, and V Clear my selection

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Calculate the Aran Hº for the reaction 2 Fe(s) + O2(g) → Fer Os (s) using the reactions below.
1
1 Fe(s) + 3 H₂O(l) → Fe(OH)3 (8) +
H₂(9) AH = +161 kJ/mol
Aran H = -286 kJ/mol
2 H₂(g) + O₂ → H₂O(1)
3 Fe₂O3 (8) + 3 H₂O(l) → 2 Fe(OH), (8) Ara H+289 kJ/mol
Which of the statements below are false for the calculation?
1. Reaction 1 must be multiplied by 2 to give 2 Fe(s) + 6 H₂O(1)→2 Fe(OH),(s) + 3 H₂(g), Ar H=+322 kJ/mol.
II. Reaction 1 must be divided by 3 to give Fe(s) + H₂O(1)→ Fe(OH),(s) + H₂(g), Aram H = +53.67 kJ/mol.
III. Reaction 2 must be multiplied by 3 to give 3 H₂(g) + O₂ + 3 H₂O(1), AH-858 kJ/mol.
IV. Reaction 3 must be reversed to give 2 Fe(OH)3(s) → Fe₂O3(s) + 3 H₂O(1), AH = 289 kJ/mol.
V. The Aren Ho for 2 Fe(s) + O₂(g) → Fe₂O3 (8) is 825 kJ/mol.
II, IV, and V
I and IV
II and IV
II, III, and V
I, III, and V
Clear my selection
00
Transcribed Image Text:Calculate the Aran Hº for the reaction 2 Fe(s) + O2(g) → Fer Os (s) using the reactions below. 1 1 Fe(s) + 3 H₂O(l) → Fe(OH)3 (8) + H₂(9) AH = +161 kJ/mol Aran H = -286 kJ/mol 2 H₂(g) + O₂ → H₂O(1) 3 Fe₂O3 (8) + 3 H₂O(l) → 2 Fe(OH), (8) Ara H+289 kJ/mol Which of the statements below are false for the calculation? 1. Reaction 1 must be multiplied by 2 to give 2 Fe(s) + 6 H₂O(1)→2 Fe(OH),(s) + 3 H₂(g), Ar H=+322 kJ/mol. II. Reaction 1 must be divided by 3 to give Fe(s) + H₂O(1)→ Fe(OH),(s) + H₂(g), Aram H = +53.67 kJ/mol. III. Reaction 2 must be multiplied by 3 to give 3 H₂(g) + O₂ + 3 H₂O(1), AH-858 kJ/mol. IV. Reaction 3 must be reversed to give 2 Fe(OH)3(s) → Fe₂O3(s) + 3 H₂O(1), AH = 289 kJ/mol. V. The Aren Ho for 2 Fe(s) + O₂(g) → Fe₂O3 (8) is 825 kJ/mol. II, IV, and V I and IV II and IV II, III, and V I, III, and V Clear my selection 00
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