Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question
How did we get 807kJ from question a？how did we get 128kJ for b ？is there a step by step explanation？
66. Using the bond energies in Table 7.3, determine the approximate enthalpy change for each of the following reactions: (a) Cl, (g) + 3F,(g) → 2CIF, (g) (b) H,C=CH,(g) + H,(g) → H,CCH,(g) Solution (a) -807 kJ; ED De-c + 4Dc-H + Du-H - Dc-c - 6Dc-H: = 611 + 4(415) + 436 - = -128 kJ DH° ZDbonds formed bonds broken %3D C-C (b) 345 - 6(415) |
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Transcribed Image Text:66. Using the bond energies in Table 7.3, determine the approximate enthalpy change for each of the following reactions: (a) Cl, (g) + 3F,(g) → 2CIF, (g) (b) H,C=CH,(g) + H,(g) → H,CCH,(g) Solution (a) -807 kJ; ED De-c + 4Dc-H + Du-H - Dc-c - 6Dc-H: = 611 + 4(415) + 436 - = -128 kJ DH° ZDbonds formed bonds broken %3D C-C (b) 345 - 6(415) |
Bond Bond Energy Bond Bond Energy Bond Bond Energy H-H 436 C-S 260 F-CI 255 H-C 415 C-CI 330 F-Br 235 H-N 390 C-Br 275 Si-Si 230 H-O 464 C-I 240 SI-P 215 H-F 569 N-N 160 Si-S 225 H-Si 395 N = N 418 Si-CI 359 H-P 320 N = N 946 Si-Br 290 H-S 340 N-O 200 Si-l 215 H-CI 432 N-F 270 P-P 215 H-Br 370 NAP 210 P-S 230 H-I 295 N-CI 200 P-CI 330 C-C 345 N-Br 245 P-Br 270 C = C 611 O-0 140 P-I 215 C = C O = 0 S-S 215 837 498 C-N 290 O-F 160 S-CI 250 C = N 615 O-Si 370 S-Br 215 C = N O-P 350 CI-CI 243 891 C-O 350 O-CI 205 CI-Br 220 C = 0 741 200 CI-I 210 MacBook Air C = 0 1080 F-F 160 Br-Br 190 C-F 439 F-Si 540 Br-l 180 C-Si 360 F-P 489 150 C-P 265 F-S 285
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Transcribed Image Text:Bond Bond Energy Bond Bond Energy Bond Bond Energy H-H 436 C-S 260 F-CI 255 H-C 415 C-CI 330 F-Br 235 H-N 390 C-Br 275 Si-Si 230 H-O 464 C-I 240 SI-P 215 H-F 569 N-N 160 Si-S 225 H-Si 395 N = N 418 Si-CI 359 H-P 320 N = N 946 Si-Br 290 H-S 340 N-O 200 Si-l 215 H-CI 432 N-F 270 P-P 215 H-Br 370 NAP 210 P-S 230 H-I 295 N-CI 200 P-CI 330 C-C 345 N-Br 245 P-Br 270 C = C 611 O-0 140 P-I 215 C = C O = 0 S-S 215 837 498 C-N 290 O-F 160 S-CI 250 C = N 615 O-Si 370 S-Br 215 C = N O-P 350 CI-CI 243 891 C-O 350 O-CI 205 CI-Br 220 C = 0 741 200 CI-I 210 MacBook Air C = 0 1080 F-F 160 Br-Br 190 C-F 439 F-Si 540 Br-l 180 C-Si 360 F-P 489 150 C-P 265 F-S 285
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