14. Calculate the standard enthalpy change for the reaction: 2Al(s) + Fe2O3(s) 2Fe(s) + Al2O3(s) given that: 2Al(s) + 3/202(g) → Al2O3(s) 2Fe(s) + 3/202(g) → Fe2O3(s) AH°x=-1675.7kJ/mol AH x =-824.2kJ/mol

From the change in internal energy, AE, given for 40 °C, calculate the change in enthalpy, AH, at the same temperature for the reaction: N202 (g) → N2 (g) + O2 (g) AE = -151.3 kJ O -153.2 kJ -153.8 kJ O -155.2 kJ O -148.7 kJ O -151.3 kJ A Moving to another question will save this response. MacBook Air 吕口 F3 F4 F5 F6 # $4 3. 4 6.

Calculate the enthalpy of reaction for the following reaction: Fe₂O3(s) + 3CO(g) → 2Fe(s) + 3CO₂(g) AH,(Fe₂O3(s)) = -824.2 kJ/mol AH(CO(g)) = -110.5 AH,(Fe(s)) = ? AH(CO₂(g)) = -393.5 kJ/mol Answer: How much energy in kJ is required to heat a calorimeter whose heat capacity is 113.4 J/°C from 23.5°C to 55.0°C?

In a popular television series, the two characters use thermite to assist with breaking into a chemical storage facility because the reaction between aluminum and iron(III) oxide produces a tremendous amount of heat. If they began with 10.0 g of Al, how many kJ of heat would be released? 29. 2 Al(s) + Fe,O3(s) → Al,O;(s) + 2 Fe(s) AH = -852 kJ 158 kJ A) B) 236 kJ 472 kJ D) None of the above

Aluminum metal can be produced by reducing solid aluminum oxide (Al2O3) with carbon (graphite). Carbon monoxide is the other product. What is the enthalpy change (AH° in kJ) when 25.0 g of aluminum metal is produced in this manner? You will need to balance the chemical equation. Enthalpies of formation (in kJ mol¯¹): Al2O3(s) -1675.7 CO(g) -110.5 Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a -623 b 623 с -734 d 734

What is the enthalpy change when 47.6 g Al completely react, given the reaction below?   The molar mass of Al = 27.0 g/mol.  Fe2O3(s) + 2 Al(s) → Al2O3(s) + 2 Fe(s)        ΔH°rxn = -852 kJ

A chemist measures the enthalpy change AH during the following reaction: 2 Al(OH),(s)-Al,0,(s) + 3H,0(1) AH=41. kJ Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction ΔΗ 3AI,0,(s) + 9H,0() 6Al(OH),(s) Al,0,(s) + 3H,0() 2Al (OH), (s) Al(OH),(6) - Al,0,(0) + ,00 1 Al,0,(5) + H,0() O kJ Explanation Check 2021 McGra M B

Calculate the change in enthalpy of the following reaction. ΔH (Fe3O4) = -1120.9 kJ ΔH (Al2O3) = -1669.8 kJ  8Al(s) + 3Fe3O4(s) -> 4Al2O3(s) + 9 Fe(s

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Determine the enthalpy of reaction for HCI(g) + NANO,(s) → HNO,(1) + NaCI(s) 2NACI(s) + H,O(1) → 2HCI(g) + Na O(s) AH° = -507.1 kJ/mol NO(g) + NO,(g) + Na¸O(s) → 2NAÑO,(s) AH° = -427.0 kJ/mol NO(g) + NO,(g) → NO(g) + 0,(g) AH° = -43.01 kJ/mol 2HNO (1) → NO(g) + 0,(g) + H,O(1) AH° = +34.02 kJ/mol