(c) What will be the change in vertical stress below point E in Figure Q1b at the depth of 5m below the foundation due to q=100 kPa from the foundation. E. 1.5m 1.5m 2m 5m
Q: 3. An earth embankment is shown in Figure 3.48. Determine the stress increase at point B due to the…
A:
Q: P2: A flexible L-shaped raft shown in Figure applies a uniform pressure of 60 kN/m? to the…
A: Stress Increase at Any Depth z Using Boussinesq Equation :σ=3Q2πz2[1(1+rz2)52]Where Q = Applied…
Q: Practice Problem: Refer to Figure 3.70, a flexible square area is subjected to a uniformly…
A: Given: The distributed load (q) is 100 kN/m2. The depth is 4 m. Consider the figure,
Q: A concentrated load of 45000 Ib acts at foundation level at a depth of 6.56 ft below ground surface.…
A: Solution; Given that; Q=45000 lb r=16.4 ft z=32.8 ft
Q: ,7 For the following soil element at a depth of 20 m, find: (a) The principal stresses, assuming the…
A: Normal Stress: It is defined as the stress which is induced due to the application of axial force on…
Q: Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure P6.2).…
A: Applying Boussinesq's Equation: ∆σz=3P2πz21+rz25/2 ...(1)
Q: A rectangular foundation of 4m x 6m (as shown in Figure 4) transmits a stress of 150 kPa on the…
A: given stress σ=150kPa
Q: A rectangular foundation 4 m × 6 m (Figure P7.20) trans- mits a stress of 100 kPa on the surface of…
A: We have to find the value of depth at which the increase in vertical stress below A less than 10% of…
Q: Point loads of magnitude 9, 18, and 27 kN act at A, B, and C, respectively (Figure 8.23). Determine…
A: Boussinesq’s formula for calculating stress below point load:
Q: Using Boussinesq's Equation determine the vertical stress increase A6z, at point Cat a depth 3.0…
A:
Q: A flexible rectangular area is subjected to a uniformly distributed load of q = 225 kN/m?. Determine…
A: Point A q=225 kN/m2B=4 m L=8 mz=3 mm=Bz=43=1.33n=Lz=83=2.67 From Table,…
Q: Compute the vertical normal stress, o, at points A, B, and C in Figure 9.11. 15.0 kN/m3: 0.9 m 2.0 m…
A: Density of soil 1, γ1 =15 KNm3Density of soil, γ2 =16.8 KNm3Density of soil, γ3 =17.2 KNm3
Q: A 4.5m square foundation exerts a uniform pressure of 200kPa on a soil. Determine (i) The vertical…
A: Given Data:Size of footing = 4.5×4.5 Pressure = 200kpaIt is asked to find vertical stress at:(i)…
Q: A flexible rectangular area measures 2.5X5 m in plan. It supports a load of 150 kN/m. Determine the…
A:
Q: 10. A load on an infinitely long strip increases linearly from zero to a maximum of 100 kPa across…
A: Vertical stress and horizontal stress are principal stresses. The vertical stress on element A can…
Q: Q2/ For the uniformly distributed loaded area as shown below, estimate the vertical stress at point…
A: A uniformly distributed load (UDL) is a load that is distributed across the region of an element…
Q: A rectangular foundation 4 m x 6 m transmits stress of 300 kPa on the surface of a soil deposit, as…
A: r=4m z=5m
Q: 10.19 Refer to Figure 10.46. A flexible rectangular area is subjected to a uniformly dis- tributed…
A: Given data: q = 225 kN/m2 Total load on rectangular area = Q= q×Area=225 kN/m2×6 m×3 m=4050 kN r =…
Q: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine…
A: Given: Uniform strip load, q = 900 lb/ft2 Width, B = 36 ft Depth of point, z = 15 ft x = 27 ft
Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING
A: q =γ H = 17 x 10 = 170 kN/m², Z= 5 mThe embankment is divided into blocks as shown in figure for…
Q: Refer to Figure below. Point loads of magnitude 500 KN, 750 KN, 800 KN, and D00 KN act at A C. E,…
A: We will use boussinesq equation.
Q: | A uniformly distributed line load of 500 kN/m is acting on the ground surface. Based on…
A: Given data: A uniformly distributed line load, q' = 500 kN/m
Q: Use the approximate method to estimate the stress (kPa) under the center of a rectangular loaded…
A:
Q: PISBILM N8. For the embankment shown in Figure below, determine the vertical stress increases at…
A:
Q: A 5-m-diameter tank supported on the surface of a soil deposit imposes a bearing pressure of 225 kPa…
A: Given data Diameter of tank, D =5m Depth of stress calculation point, Z = 4m Bearing pressure due to…
Q: Ex2: An embankment shown in the figure is constructed. compute the vertical stress increment under…
A: Calculating q q=γ1Hq = 19.2x6q = 115.2 kN/m2 σz = ql5σz=qπB1+B2B1α1+α2-B2B1α2 Here,…
Q: ) A uniform pressure of 150 kN/m acts on a 3 m*4.5 m rectangular rea. Since the point X is at the…
A: by using westergard theory Qz=wπz2 11+2rz23/2where,w=pointed loadz=depth below the midpointr=any…
Q: A shallow foundation 25 x 18 m carries a uniform pressure of 175 k N / m 2 . Determine the vertical…
A:
Q: A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs =…
A:
Q: Determine the increase in vertical stress at a depth of 5 m below the centroid of the foundation…
A: Consider the given figure.
Q: Ex2: An embankment shown in the figure is constructed. compute the vertical stress increment under…
A:
Q: Problem 2: A soil element is shown 5.4 kN/m2 in the figure on the right. The magnitude of stresses…
A: Answer:- It can solve by the help of formula for major and minor principal stresses.…
Q: 11.6 The coordinates of two points on the virgin compression curve are as follows: o' (lb/ft²) 2000…
A: GIVEN: The coordinates of two points on the virgin compression curve are - TO DETERMINE: The…
Q: A rectangular foundation 4 m x 6m (Figure P1.20) trans- mits a stress of 100 kPa on the surface of a…
A: The load on the foundation is calculated as,
Q: H.Q 4 Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure below).…
A:
Q: a) Referring to Figure Q2 (a), the vertical stress increase at point A is 25 kN/m2 due to…
A: To find out the value of q2.
Q: A group of 4 point loads 3000 kN each are acting on the vertices of a rectangular area of length 5 m…
A:
Q: Problem 3 Determine the increase in vertical stress at a depth of 2m in the soil below point A due…
A: given data used below as shown in figure at depth 2m,dead load 100kN/m2
Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING
A: We are given the following data
Q: Referring in the Fig. 2 below, B = 6m and q =150 kPa. For Point P, z 2m and x = 1.5m. Determine the…
A: Given Data: The width of the strip footing is B=6 m. The loading of the strip footing is q=150 kPa.…
Q: H.Q 4 Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure below).…
A: Given that: Point load at B, QB=100 kN Point load at C, QC=200 kN…
Q: The plan of a flexible rectangular loaded area is shown in Figure 6.30. The uniformly distributed…
A: Solution: The equation for determining the increase in stress on a flexible rectangular area at a…
Q: Refer to Figure, q1 = 90 kN/m; q2 %3D 325 kN/m; x1 = 4 m; x2 = 2.5 m; z = 3 m. the vertical stress…
A:
Q: Q2 (a) Referring to Figure Q2 (a), the vertical stress increase at point A is 25 kN/m² due to…
A: Figure is as shown
Q: (c) Figure 3.2 shows the general arrangement for a total stress analysis of a clay slope. Prove from…
A:
Q: Figure P.8.12 shows an embankment load on a silty clay soil layer. Determine the stress increase at…
A:
Q: 3.2 Three point loads, 10 000 kN, 7500 kN and 9000 kN, act in line 5 m apart on the surface of a…
A:
Q: CEN-333 Geotechnical
A: Boussinqi's equation: σZ=QZr32π11+rZ252where,Z=Depth of the pointQ=point load actingr=radial…
Step by step
Solved in 2 steps with 2 images
- Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine the increase in vertical stress at point A located z = 15 ft below the surface. Given: x = 27 ft. Figure P6.4Q4: For the soil element shown, compute the stresses acting on the plane inclined by 40° with the horizontal plane then draw Mohr circle and place the stresses with respect to O.P. 20kPa 35kPa 100kPa 300 40°An eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 4 ft 2 ft Figure P6.18 Qu 2 ft → -5 ft Y = 105 lb/ft³ Groundwater table Ysat 118 lb/ft³ c' = 0 $' = 35° =
- O A rectangular foundation 4 m × 6 m (Figure P7.20) trans- mits a stress of 100 kPa on the surface of a soil deposit. Plot the distribution of increases of vertical stresses with depth under points A, B, and C up to a depth of 20 m. At what depth is the increase in vertical stress below A less than 10% of the surface stress? B 6 m -2 m- A 2 m -4 m FIGURE P7.20Problem 2: A rectangular foundation of 4m × 6m (as shown in Figure P2) transmits a stress of 150 kPa on the surface of a soil deposit. Plot the distribution of induced vertical stresses with depth under points A (the centre of the rectangle), B and C up to a depth of 20 m. 6m 4m A Figure P2 B 2m с 2mBased on the geometry calculation of the drawn Mohr circle, what is the minor principal stress (o3) [unit: kN/m2]. oy= 120 kN/m2, T = 40 kN/m?, ơy = 300 kN/m2, and e = 20°. %3D B A T. Ty
- help meA short rectangular post supports a compressive load of P = 210 kN as shown. A top view of the post showing the location where load P is applied to the top of the post is also shown. Determine the vertical normal stress at corner d of the post. -9.14 MPa -15.12 MPa -11.20 MPa -12.06 MPa -14.02 MPaWhich of the following best give the value of the lateral torsional modification factor, Cb, of the figure shown. M 12.5Mmax C = 2.5Mmax+3MA + 4MB + 3Mc тах ) 1.67 1.0 2.27 O 1.5
- Figure Q1(a) shows a 3.5 m height of 150 mm x 250 mm column, is supporting à vertical load at the top of the column. The column is rigidly supported by the foundation and rigidly connected with the beams. Given that Young's modulus, E = 15,500 N/mm2 and yield capacity, Oyield QI. 20 MPа. %3D 300 mm 250 mm 3.5 m Foundation Isometric view of column Figure Q1(a) (i) Calculate the effective length of column for x-x and y-y axes, respectively. (a) (ii) Determine the critical load of column for x-x and y-y axes, respectively.SITUATION. Based on the figure shown a hallow steel pipe with external diameter Do of 200mm has a length of 3m. Use E = 200 GPa. Zoom image 179.3 165.2 172.5 Pipe External Diameter, Do Thickness, t If P = 400 KN, find the maximum internal diameter D; without exceeding a stress of 65 MPa in the pipe in millimeter. 186.8 Base Plate Diameter, D Thickness, t Concrete OFFThe principal stress orientation and maximum in-plane stress orientation are always on Mohr's circle. from each other, which shows up as O 90 degrees offset; 45 degrees offset O opposite; tangents O orthogonal; parallel O45 degrees offset; 90 degrees offset