A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.

A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter9: In Situ Stresses

Section: Chapter Questions

Problem 9.12P

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A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa. Question 1: A. 1.94 Question 1: B. 3.99 Question 1: C. 6.44 Question 1: D. 8.49 Question 2: A. 168.9 Question 2: B. 44.1 Question 2: C. 120.1 Question 2: D. 124.8 Question 3: A. 1.83 Question 3: B. 7.67 Question 3: C. 3.17 Question 3: D. 6.33
A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.
Ground surface 2. The soil profile for a proposed construction site is shown. The groundwater table is located 2 m below the ground surface. Assume geostatic conditions and ignore any negative pore-water pressures due to capillary rise. Yt = 13.2 kN/m 2. Sand Ysat =? G, = 2.70 n= 0.5 (a) What is the effective stress (kPa) at point A? (Ans: 43 kPa) (b) What is the effective stress (kPa) at point B? (Ans: 82 kPa) (c) Ten years from now, the depth of the groundwater table will change, resulting in a new effective stress at point B of 72.6 kPa. Based on this information, how far below the ground surface will the new location of the groundwater table be? (Ans: 0 m; GWT is at the ground surface) A Clay Ysat = 19.6 kN/m
A 5m thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.5m thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is locate 4.5m from the ground surface. 1. at what depth would the vertical effective stress be equal to 120kpa?2. what is the vertical effective stress at a depth 9m below the ground surface? 3. what depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100kpa?
2. At what depth would total the vertical stress in a deep deposit of clay (e = 1.1, G;= 2.74) be 100 kPa if the water table is 1 m below the ground surface and the above the water surface a saturation degree of 90 % exists. What is the effective stress at the same depth? 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is nat- urally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to develop due to the nature of the soil in ques- tion. Compute the effective stresses at the end of expected capillary action, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Average S, Capil- G, D10 lary Zone Clay 2.71 0.98 0.0125 25 55% Figu Sand 2.74 0.93 N.A. N.A. N.A.
The water table in a deposit of uniform sand is located at 2 m below the ground level. Assuming the soil above the water table be dry and the void ratio is 0.75. The effective stress (in kN/m2, rounded off to nearest integer) at a depth of 5 m below the ground level is (upto 2 decimal places), Take G = 2.65 and Y₁ =9.81 kN/m².
Problem 1 A ground profile consists of 2 m of silty sand underlain by 3 m of clay. The ground water table is 3 m below the ground surface. The sand has a unit weight of 14 kN/m3. The clay has unit weight of 16 kN/m3 above the water table and 20 kN/m3 below the water table. a. Determine the total stress at bottom of the clay b. Determine the pore water pressure at the bottom of the clay c. Determine the effective stress at the bottom of the clay Problem 2 50 ft thick sand is underlain by 25 ft clay. The ground water table, initially at the ground surface, was lowered to a depth of 25 ft below the ground. After such lowering, the degree of saturation of the sand above water table was lowered to 20%. Saturated and dry unit weight of sand are 135 pcf and 116 pcf respectively. The saturated unit weight of clay is 120 pcf. a. What is the vertical effective pressure at the midheight of the clay layer before lowering of the water table in psf? b. What is the vertical effective pressure at the…
Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.59, e = 0.61. Properties of clay: Gs = 2.74, e = 0.86. Round off to two decimal places. Answer: 13.95
The saturated unit weight of a 10 m thick clay layer is 20 kN/m3. Calculate the vertical effective stress at a depth of 5 m if the groundwater level is at the surface and select the correct answer from the below: O A. Total stress = 50 kPa Porewater pressure = 48.5 kPa Effective stress = 52.1 kPa O B. Total stress = 120 kPa Porewater pressure = 40 kPa Effective stress = 60 kPa O C. Total stress = 100 kPa Porewater pressure = 49.1 kPa Effective stress = 50.1 Pa O D. Total stress 110 kPa Porewater pressure = 42.2 kPa Effective stress = 55 kPa
The soil profile consists of 5m sand underlain by 13 m layer of clay. The ground water table is at a depth 2.8 m below the surface. The sand has a unit weight of 19 kN per cu. Meter above the ground water table and the saturated unit weight below was 20 kN per cu. meter. The saturated unit weight of the clay is 15.7 kN per cu. meter. At a depth of 11 m determine the following:a. Total stressb. Pore water pressurec. Effective stress.....
Given the soil profile as shown. 4.5 m e, = 0.7, S = 0.85 GWL 5 m w = 28% a) Determine the effective stress at the bottom in kPa. b) Determine how high should the water table rise up (in m) so that the effective stress at bottom is 100 kPa c) Determine the effective stress if the water level rises 2m above the surface.
6. From the given soil profile, the groundwater table is located 2m below the ground level. (See picture below) Compute the horizontal effective stress at point A. (Answer: 53.36 kPa) Compute the lateral effective stress at point A if the lateral earth pressure coefficient at rest is K0=0.50. (Answer: 26.68 kPa) Compute the lateral total stress at point A. (Answer: 56.11 m)

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		Question 1: A. 1.94
		Question 1: B. 3.99
		Question 1: C. 6.44
		Question 1: D. 8.49
		Question 2: A. 168.9
		Question 2: B. 44.1
		Question 2: C. 120.1
		Question 2: D. 124.8
		Question 3: A. 1.83
		Question 3: B. 7.67
		Question 3: C. 3.17
		Question 3: D. 6.33