An eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 4 ft 2 ft Figure P6.18 Qu 2 ft → -5 ft Y = 105 lb/ft³ Groundwater table = Ysat c' = 0 $' = 35° 118 lb/ft³

Example 12.6 A square foundation is shown in Figure 12.9. Assume that the load eccentricity e 0.5 ft. Determine the ultimate load, Qut Sand y = 115 lb/ft d' = 30° 5ft X5ft c' 0 Figure 12.9

Answer in three decimal places please

4. A flexible foundation is shown below, determine the immediate settlement below the center of the foundation. Assume the thickness of the soil below the foundation is 20 meters. Following is the variation of the modulus of the soil below the foundation. Es (kN/m²) Depth below the foundation(m) 0-4 4-8 8-20 >20 1.2m 10000 8000 12000 8 90 = 150kPa BXL = 2m x 2m Ug = 0.3