Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score between negative 1.62 and 1.62. The probability is ​(Round to four decimal places as​ needed.)

Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose reading from the horse (in mg/100 mg).  92  87  82  107  99  109  85  89  The sample mean x-bar is 93.8. Let x be a random variable representing glucose readings taken from gentle Ben.  We may assume x has a normal distribution, and we know from past experience that the standard deviation = 12.5. The mean glucose level for horses should be mu = 85mg/100gl.  Do these data indicate that gentle Ben have a overall average glucose level higher than 85? Use alpha = 0.05 A- Compute z value of the sample stasistic test. Round answer to 2 decimal places B- Find (or estimte) the P-Value . Round answer to 4 decimal places  I get 1.99 for the z value but cannot come up with correct p-value.

Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches.  A particular man is 80 inches tall.  Find the z-score of his height.  (Round to two decimal places.)

Assume that adults have IQ scores that are normally distributed with a mean of 104.7 and a standard deviation of 24.1. Find the probability that a randomly selected adult has an IQ greater than 137.1. (Hint: Draw a graph.) The probability that a randomly selected adult from this group has an IQ greater than 137.1 is (Round to four decimal places as needed.)

A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1458 and the standard deviation was 312. The test scores of four students selected at random are 1860, 1220, 2150, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1860 is (Round to two decimal plaes as needed.)

Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…