Answer: F₂/F₁ =

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Part 2
Derive a compatibility equation using force-deformation relationships substituted into a geometry-of-deformation
relationship. Express the compatibility equation here as the ratio of the force in the oak block, F2, to the force in each
steel plate, F₁.
Answer: F₂/F₁ = i
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Transcribed Image Text:Part 2 Derive a compatibility equation using force-deformation relationships substituted into a geometry-of-deformation relationship. Express the compatibility equation here as the ratio of the force in the oak block, F2, to the force in each steel plate, F₁. Answer: F₂/F₁ = i Save for Later Attempts: 0 of 1 used Submit Answer
The 200 x 200 x 1,250-mm oak [E = 12 GPa] block (2) shown is reinforced by bolting two 5 x 200 x 1,250 mm steel [E = 200 GPa]
plates (1) to opposite sides of the block. A concentrated load of 300 kN is applied to a rigid cap. Assume P = 300 kN, L = 1.25 m.
Determine
(a) the normal stresses in the steel plates (1) and the oak block (2).
(b) the shortening of the block when the load is applied.
B
(1)
Answers:
Calculate the cross-sectional area of each steel plate, A₁, and the cross-sectional area of the oak block, A2.
A₁ =
A₂ =
i
i
(1)
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L
mm²
mm²
Attempts: 0 of 1 used
Submit Answer
Transcribed Image Text:The 200 x 200 x 1,250-mm oak [E = 12 GPa] block (2) shown is reinforced by bolting two 5 x 200 x 1,250 mm steel [E = 200 GPa] plates (1) to opposite sides of the block. A concentrated load of 300 kN is applied to a rigid cap. Assume P = 300 kN, L = 1.25 m. Determine (a) the normal stresses in the steel plates (1) and the oak block (2). (b) the shortening of the block when the load is applied. B (1) Answers: Calculate the cross-sectional area of each steel plate, A₁, and the cross-sectional area of the oak block, A2. A₁ = A₂ = i i (1) Save for Later L mm² mm² Attempts: 0 of 1 used Submit Answer
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