Answered: An ion's position vector is initially…

Name: An ion's position vector is initially r→=(-3.7m)î+(-6.4m)ĵ+(9.3m)k̂,
Uploaded: 2024-03-20T06:57:47.000Z
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Description: An ion's position vector is initially r→=(-3.7m)î+(-6.4m)ĵ+(9.3m)k̂, and 9.4 s later it is r→=(8.3m)î+(5.0m)ĵ+(8.2m)k̂. In unit-vector notation, what is its average velocity during the 9.4 s?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An ion's position vector is initially r→=(-3.7m)î+(-6.4m)ĵ+(9.3m)k̂, and 9.4 s later it is r→=(8.3m)î+(5.0m)ĵ+(8.2m)k̂. In unit-vector notation, what is its average velocity during the 9.4 s?

Expert Solution

Step 1

Given data

The initial position is given as $r_{1} = (- 3.7 m) \hat{i} + (- 6.4 m) \hat{j} + (9.3 m) \hat{k}$ .
The final position is given as $r_{2} = (8.3 m) \hat{i} + (5.0 m) \hat{j} + (8.2 m) \hat{k}$ .
The time duration is given as t = 9.4 s.

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