The velocity of a particle which moves along the s-axis is given by v = 2 + 5t^(3/2) where t is in seconds and v displacement s, velocity v, and acceleration a when t = 4s. The particle is at the origin s = 0 when t = 0.

The velocity of a particle which moves along the s-axis is given by v = 2 + 5t^(3/2) where t is in seconds and v displacement s, velocity v, and acceleration a when t = 4s. The particle is at the origin s = 0 when t = 0.

Name: Help me answer the problem question write it on paper with a complete
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Help me answer the problem question write it on paper with a complete solution and box the final answer with their unit. Thank you again. The velocity of a particle which moves along the s-axis is given by v = 2 + 5t^(3/2) where t is in seconds and v

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 6P: At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of...

See similar textbooks

Similar questions

The velocity of a particle (in meters per second) is given by v = 16t'i+ 4tj + (5t + 2)k, wheret is in seconds. If the particle is at the origin when t = 0, determine the magnitude of the particle's acceleration when t = 2 s. Also, what is the x, y, z coordinate position of the particle at this instant? a = 75.16 m s^-2 ;r = (36.67, 10, 8) a = 80.16 m s^-2;r = (42.67, 16, 14) a = 85.16 m s^-2;r = (48.67, 24, 20) O None of the choices
An ion's position vector is initially r= 5i – 6j + 2k, and 10 slater it is r= -2i + 8j – 2k, all in meters. In unit-vector notation, what is its average velocity during the 10 s?
The coordinates of a particle moving along a curve are x(t) = -2t2 +15 and y(t) = t2 -10t + 15 , m whent is in seconds. Calculate the magnitude of velocity and acceleration when t= 5 sec.
A particle starts moving from the origin in xy-plane with initial velocity =-2i +6j m/s. If the particle's velocity 4s later is v, = 4i +12jm/s, what is the acceleration of the particle assuming constant (in m/s )?
A particle initially is moving at a velocity with Cartesian components (5.0 m/s, 4.0 m/s) and 5.6 s later it is moving at a velocity with components (8.0 m/s, 0.0 m/s). What is the magnitude of its average acceleration, in m/s2?
Particle is moving on a straight line and where velocity varies with its displacement as U=V4+4s. Find displacement at t = 2s if s=o at t=o. I am not able to figure out how to approach this.
A particle leaves the origin with its initial velocity given by v=5.2i +14j m/s, undergoing constant acceleration a=- m/s?. When does the particle cross the y axis?
A particle moves along the x-axis with an acceleration of a = 18t, where a has units of m/s/s. If the particle at time t = 0 is at the origin with a velocity of -12 m/s, what is its position at t = 4.0s?
person stands at the edge of a cliff and throws a pebble horizontally over the edge with a speed of v0 = 15.0 m/s.The pebble leaves his hand at a height of h = 46.0 mabove level ground at tge bottom of the cliff. How long (in s) after being released does the pebble strike the ground below the cliff?. With what speed (in m/s) and angle of impact (in degrees clockwise from the +x-axis) does the pebble land?
Question 5:" Starting from x = o with no initial velocity, a particle is given an acceleration a = 0.1V7 + 16, where a and v are expressed in ft/s? and ft/s, respectively. Determine (a) the position of the particle when v = 3 it/s, (b) the speed and acceleration of the particle when x = 4 ft. Write your answer in the format (a. x = %3D ft; b. v_sp = ft/s , a ft/s^2) Your answer
The acceleration vector of a particle is giving by a = -27 t2 j m/s4. The particle is located at the origin at t = 0 s and has an initial velocity Vo = 2(m/s) i + 3(m/s) j. Find: a) The velocity of the particle as a function of time. b) The maximum height the particle reaches.
WRITE THE ANSWER IN 10 MINUTES PLEASE ! ! ! A particle is moving in three dimensions and its position vector is given by; r(t)= (3t^2+3.5t)i + (2.5t−4.8)j+ (2.8t^3+4.5t)k where r is in meters and ?t is in seconds. Determine the magnitude of the instantaneous acceleration at t=3s. Express your answer in units of m/s2 using one decimal place.