Initially, a bicycle is at the position ř = (130 m)î + (210 m)j. After 120 s, the position of the particle is ř = (110 m)î + (240 m)j. What is the average velocity vector of the bicycle in that time tinterval? O Tay = (0.17 m/s))î + (–0.25 m/s)ĵ O ūay = (0.25 m/s)î + (–0.17 m/s)j O Tay = (-0.25 m/s)î + (0.17 m/s)j O Tay = (-0.17 m/s)î + (0.25 m/s)j

Initially, a bicycle is at the position ř = (130 m)î + (210 m)j. After 120 s, the position of the particle is ř = (110 m)î + (240 m)j. What is the average velocity vector of the bicycle in that time tinterval? O Tay = (0.17 m/s))î + (–0.25 m/s)ĵ O ūay = (0.25 m/s)î + (–0.17 m/s)j O Tay = (-0.25 m/s)î + (0.17 m/s)j O Tay = (-0.17 m/s)î + (0.25 m/s)j

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 113CP: The position of a particle moving along the x -axis varies with time according to x(t)=5.0t24.0t3 ....

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