An aerated BOD bottle is filled with substrate and microbial cells. You have determined the following parameters for this mixture: - Substrate yield, Y=0.60mg/L biomass /mg/L substrate - Specific growth rate, μ=2.0 day −1 - Rate of substrate utilization =15,000mg/L−hr - Substrate concentration =275mg/L - Half-saturation constant =25mg/L Determine: a. The microbial growth rate/biomass utilization rate. 9000mg/L−hr b. The maximum specific growth rate. 2.18 / day c. The biomass concentration. 4500mg/L

Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter10: Oxidation, Degradation, Corrosion, Electroprocessing, Batteries, And Fuel Cells
Section: Chapter Questions
Problem 10.1P
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V3. An aerated BOD bottle is filled with substrate and microbial cells. You have determined the following parameters for this mixture: - Substrate yield, Y=0.60mg/L biomass /mg/L substrate - Specific growth rate, μ=2.0 day −1 - Rate of substrate utilization =15,000mg/L−hr - Substrate concentration =275mg/L - Half-saturation constant =25mg/L Determine: a. The microbial growth rate/biomass utilization rate. 9000mg/L−hr b. The maximum specific growth rate. 2.18 / day c. The biomass concentration. 4500mg/L
An aerated BOD bottle is filled with substrate and microbial cells. You have determined the
following parameters for this mixture:
o
Substrate yield, Y = 0.60 mg/L biomass / mg/L substrate
Specific growth rate, μ = 2.0 day¹
o
Rate of substrate utilization = 15,000 mg/L-hr
o Substrate concentration = 275 mg/L
o Half-saturation constant = 25 mg/L
Determine:
a. The microbial growth rate/biomass utilization rate. 9000 mg/L-hr
b. The maximum specific growth rate. 2.18/day
c. The biomass concentration. 4500 mg/L
Transcribed Image Text:An aerated BOD bottle is filled with substrate and microbial cells. You have determined the following parameters for this mixture: o Substrate yield, Y = 0.60 mg/L biomass / mg/L substrate Specific growth rate, μ = 2.0 day¹ o Rate of substrate utilization = 15,000 mg/L-hr o Substrate concentration = 275 mg/L o Half-saturation constant = 25 mg/L Determine: a. The microbial growth rate/biomass utilization rate. 9000 mg/L-hr b. The maximum specific growth rate. 2.18/day c. The biomass concentration. 4500 mg/L
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