According to Clausius statement, it is impossible to construct a device operating on a cycle which transfers heat from Select one: O a. high temperature heat reservoir to low temperature reservoir O b. low pressure heat reservoir to high pressure reservoir O c. low temperature heat reservoir to high temperature reservoir O d. high pressure heat reservoir to low pressure reservoir

According to Clausius statement, it is impossible to construct a device operating on a cycle which transfers heat from Select one: O a. high temperature heat reservoir to low temperature reservoir O b. low pressure heat reservoir to high pressure reservoir O c. low temperature heat reservoir to high temperature reservoir O d. high pressure heat reservoir to low pressure reservoir

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter45: Domestic Refrigerators And Freezers

Section: Chapter Questions

Problem 2RQ: The operating condition for the single compressor in a household refrigerator is the lowest box...

See similar textbooks

Similar questions

a. Sketch the process on a P-V diagram b. Determine the rate of heat transfer from Boiler ( Qcv/m 1-2, in KJ/kg) c. Determine the rate of heat transfer from condenser ( Qcv/m 3-4, in KJ/Kg) d. Using the Clausius inequality to determine if the cycle is internally reversible, irreversible, or impossible. e. Determine the thermal efficiency of power cycle f. Determine the maximum thermal efficiency of power cycle ( Carnot Efficiency) g. Due to part (e & g) this cycle is___________ ? - internally reversible -internally irreversible -impossible
A heat engine has to exchange heat with -----thermal reservoir at --- different temperatures to produce work in a complete cycle. Select one: O a. one, two O b. two, two O c. two, one O d. one, one
Step: Evaluate the performance of Refrigerator 2.Refrigerator 2 is a refrigerator that operates as an ideal vapor refrigeration cycle, and uses theSame refrigerant and evaporation and condensing temperatures as Refrigerator 1.In Cooler 2, the working fluid must be admitted by the compressor only in the form of vaporsaturated, and must leave the compressor in the form of superheated steam with enthalpy equal to 1640 kJ/kg.Differently from Refrigerator 1, the cycle operates with an expansion valve (isenthalpic process).For this 2nd step, you must determine the following design parameters:a) The rate of cooling and the rate of heat rejection in the condenser.b) The power of the compressor;c) The COP of the cycle.For the energy balance, make the following considerations:- Permanent regime;- Variation of kinetic and potential energy are negligible;- Compressor and expansion valve operate adiabatically;- Evaporation and condensation steps do not involve work. Please, make it typeable,…
Q2: A simple VCRC using R-134a operates with a condensing temperature of 30°c and an evaporating temperature of -20°c .The system produces 50 kw of refrigeration. Determine the : a) Thermodynamic property values at the four main state points of the cycle, b) COP, c) Rate of refrigerant flow.
Q3)The following conditions are for simple steam power plant: Equipment Turbine inlet outlet work heat 40 bar, 320°C 1000 kJ/kg 1 bar 40 bar, 320°C condenser boiler 20 MJ/kg Calculate: 1- The specific enthalpy of the wet steam at turbine outlet. 2- The heat rejected in condenser. 3- The conditions of saturated water at boiler inlet. 4- Rankin cycle efficiency.
True or false Heat is transferred to a system by either a cheap commercially available air-sourced heat pump with coefficient of performance of just 1.5, or an expensive 100% efficient electrical resistance heater. The loss of Carnot Work Potential (Exergy destruction, or T0Sloss term) is minimum when heat is added by the cheap commercial heat pump. Heat is transferred to a system by either a cheap commercially available air-sourced heat pump with coefficient of performance of just 1.5, or an expensive 100% efficient isothermal heat source. The loss of Carnot Work Potential (Exergy destruction, or T0Sloss term) is minimum when heat is added by the isothermal heat source.
A R-134a home refrigerator operates on a simple cycle at pressures 1.8 bar-abs and 7.5 bar-abs. The refrigerant mass flow-rate is 0.005 kg/s. Fill up Tables 3a and 36. Part 3. Calculation: Performance of a Simple Refrigeration Cycle. Table Ja. Selected Thermodynamic properties of R-134a refrigerant according to the given cycle. kJ/ kg a Specific Enthalpy at suction A Specific volume at suction m/ kg kJ /g-K e Specific entropy at suction d Specific enthalpy at discharge Specific enthalpy after expansion hs4 31 kJ/ kg kJ / kg Table 3b. Performance of the home refrigerator according to its cycle of operation. kWatt a. Evaporator cooling capacity b Condenser heat rejection rate Q Cond kWatt Power required by compressor W Comp C. kWatt d Volume displacement of compressor e. Coefficient of Performance-Ref VCamp Li/s COP Ref f Coefficient of Performance-Canot COP RC & Flash-gas formed after expansion X4 kg / kg %3D
Suppose a heat engine is made out of an ideal diatomic gas taken around a cycle represented by the following PV diagram: B P2 A P1 D V1 V2 Volume (a)Briefly explain why this cycle cannot be used in reverse for refrigeration. (b)Calculate the efficiency of an "ideal" engine operating between the same temperature extremes Pressure
Untitled Question * Q2: A simple VCRC using R-134a operates with a condensing temperature of 30°c and an evaporating temperature of -20°c.The system produces 50 kw of refrigeration. Determine the : a) Thermodynamic property values at the four main state points of the cycle, b) COP, c) Rate of refrigerant flow.
Thermodynamics. Thank you for help! Make and fill in the property/energy transfer table. Make sure to fill in all 24 boxes. Plot the refrigeration cycle on a T-S diagram, label with numerical value and units. 9.65 A refrigerator with R-134a as the working fluid has a minimum temperature of -10°C and a maximum pressure of 1 MPa. Assume an ideal refrigeration cycle. Find the specific heat transfer from the cold space and that to the hot space, and the COP.
Topic: Review of steam cycles Completely solve (a) to (e).
Thermodynamics review that I cannot solve! Would appreciate some or all done out A heat engine with a thermal efficiency of 45% rejects 1000 kJ/kg of heat to a low temperature sink. 1. How much heat does it receive (kJ/kg)? 2. How much work does it produce (kJ/kg)? 3. If the cycle operates between temperatures of 400°C and 50°C,what is the maximum amount of work that this cycle can produce (kJ/kg)? 4. A Carnot heat pump operates between 273 K and 313 K, determine its Coefficient of Performance.