absorption bands at 3300 (s) and 2150 (m) cm ¹. Relative absorption intensity: (s)-strong, (m)-medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm²¹. The functional class(es) of this compound is(are) . (Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene c. terminal alkyne d. internal alkyne e. arene. f. alcohol g. ether Submit Answer h. amine. i. aldehyde or ketone j. carboxylic acid k. ester I. nitrile Retry Entire Group 9 more group attempts remaining

absorption bands at 3300 (s) and 2150 (m) cm ¹. Relative absorption intensity: (s)-strong, (m)-medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm²¹. The functional class(es) of this compound is(are) . (Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene c. terminal alkyne d. internal alkyne e. arene. f. alcohol g. ether Submit Answer h. amine. i. aldehyde or ketone j. carboxylic acid k. ester I. nitrile Retry Entire Group 9 more group attempts remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Molecular Formula: C₁1H15O₂N ¹H spectrum 160 2H, d J = 7.5 Hz 13C spectrum 140 2H, d J = 7.5 Hz 120 100 5 PPM 80 PPM 60 1H, quintet J = 7 Hz 3 1 6H. triplet J = 7 Hz 4H, quintet J = 7 Hz 40 20
Help needed with assigning the peak signals and determining the J values of this Isoamyl Acetate molecule. Thank you so much!
- (a) Compounds A and B having identical molecular formula C4H80 have the following C signals at d= 7 ·87, 29.43, 36. 87, 209· 28 ppm and 8 = 13·71, 15.69, 45· 85 and 202·80, respectively. DEPT gave a single-inverted peak for A and two inverted peaks for B. Predict the two structures of A and B, assign peaks and identify the functional groups. 13 %3D
G.317.
Please help me with this, I am trying to prepare for my final exam next week and I am just completely lost
The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A hydrocarbon exhibits no bands above 3000 but gives weak absorption at 2200 cm-1.Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly.Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm-1. The functional class(es) of this compound is(are)fill in the blank 1.(Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene h. amine c. terminal alkyne i. aldehyde or ketone d. internal alkyne j. carboxylic acid e. arene k. ester f. alcohol l. nitrile g. ether
5 Molecular formula = C7H₂O₂X, where X is an atom you have to determine MS: Shows molecular ion peaks of near equal intensity at m/z = 204 and m/z = 206 IR: strong absorption at 1699 cm.¹ 3H 2H 2H 160 2H 140 120 100 PPM 80 PPM 60 2 peaks 40 ¹H spectrum 13C spectrum 20
Amplitude ° Use the supplied NMR spectrum to gain insight into methyl silicylate. Decipher the spectrum by assigning hydrogen peaks in the molecule and include it with your report. 15- 10- 5- x103 12 ہیں OH Spectrum Scan [1/1] Oil of Wintergreen START END VALUE 11.21 10.47 0.98 8.30 6.41 4.00 5.55 5.04 0.40 4.47 3.45 3.00 мили ៖ 10 8 6 ppm 2
Interpet and analyze this Infrared (IR) spectra to show the signs from the peaks and what they tell about the unknown compound.
A compound has a strong absorption at 8.37x1015 Hz. What is the Amax( in Å (angstroms)) for this compound? (Write answer in decimal form to one decimal place, for example, if answer is 75.667 then write as 75.7)
Given the following molecule, draw its predicted standard spectrum along with DEPT 90 and DEPT 135 spectra. Then, based on that picture, assign the numbered carbons on the original structure to a peak in the standard 13C spectrum. Provide a brief explanation for your choices.
5