i need answer as soon as possible A. ADJUST THE GIVEN CLOSED COMPASS TRAVERSELINE LENGTHOBSERVED BEARINGSSTACOMPUTEDCORRECTION ADJUSTED INT.FORWARD BACKWARDINTERIORANGLEANGLEAB13 m40° 649° 47ABC6.5m19° 30'70° 25'CD 20.0 m 60°DE 17.5 m 19° 2429° 45C70° 31'DEF 19 m61°290E10 m 12°GH 22.72 m 64º42'FG76°F25° 13'GНА 9.3 m23° 4266° 11'HB.DA

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Answered: A. ADJUST THE GIVEN CLOSED COMPASS…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Situation 4] From the given data ofa dosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. i. iv. Distance, m 368.76 Bearing N15°18'E S85046'E S18°30W N77035W Line АВ ВС 645.38 CD 467.86 DA 593.00
ANSWER KEY=D 108.1502m∆h 22.4596m
3. The following data if a closed traverse is shown in the technical description. The area of the closed traverse is 63147.05 sq. m. LINES AB BC CD LAT. a -240.20 -160.00 DA 179.70 Solve for the unknown variables. DEP. 120 с e -220 DMD b d f 8 2A 26460.0 X -86480.0 39534.0
Q3: A: Draw the diagram of traverse classification. B: In closed traverse ABCD. The partial coordinates were known as shown below. Determine its area by DMD method. 04 N Dofland OWODY dienstl it with (nm) dinostim Mem. AB BC CD DA ΔΧ 40 -80 -50 AY 60 100 -70
The following are the observed data for an open compass traverse. Adjust the observed directions and tabulate values accordingly. LINE LENGTH OBSERVED BEARING FORWARD BACKWARD AB BC CD DE EF FG 462.50 m 405.65 m 495.08 m 284.15 m 367.29 m 217.73 m S 40o25’ W S 55o40’ W N 36o15’ W N 73o10’ W S 44o45’ W S 20o30’ E N 40o30’ E N 55o50’ E S 35o55’ E S 73o30’ E N 44o45’ E N 21o00’ W
At a resection point P, the following horizontal angles were observed to three control poin L, M and N: MP L=121°02' 19" LP N = 112°15'03" NP M = 126°42'41" The coordinates of L, M and N are E (m) N (m) L 550 650.528 M 600.076 450.187 N 750.004 600.132 Calculate the coordinates of point P. N 112 1503 121 021126°42'41" M Figure 1. three-point resection.
From the following measured interiror angles of a five sided figure, compute the following: Station Values of Angles (No. of Measurements A 110.00 98.000 108.00 120.00 105.00 BUDE с 5 NOTE: Final answer must be in decimal degrees. HINT: Sum of Interior Angles = (n-2)*180* NAO сл 6 4 2 1 a) Probable value of Angle A. b) Probable value of Angle C. °c) Probable value of Angle D
Determine the force of all members using METHOD OF JOINT. Answer in 3 decimal places only. TRUSS MEMBERS ● FORCE COMPRESSION OR TENSION
Comproto me komo D C 105 22 Sta A B C D 118 37 E 108°28′ E B 120 28 N30°00'W MERIDIAN 87°05' DEFLECTION ANGLE A ANGLE TO THE RIGHT
SITUATION 1- Hissing Data Given: Traverse with omitted measurements. (a) Calculate the distance of line GA (b) Determine the bearing of line CD TRAVERSE DATA W/ OHITTED MEASUREMENTS UNE LENGTH (m) BEARING AB 550.00 S 80.00° W BC 295.00 N 40.00° W CD 610.00 DE 885.00 S 72.00° E EF 455.00 S 18.00° E FG 500.00 S 80.00° W GA N 30.00 W
Deflection Angle Traverse Given the bearing of each line of a closed traverse ABCDEF, determine the deflection angles of each line. Line Bearing AB S 46°17’ E BC N 23°28’ E CD N 78°55’ W DE S 56°42’ W EF S 13°00’ W FA N 76°05’ E * Sum of Deflection Angle = 360° * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. (Please answer this problem with accurate and proven solution. Thank u)
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: Line AB BC CD DA 2- Linear misclosure 3- Traverse precision Length(m) 330 866.8846 411.0045 827 Sum=2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C 1358.7 D 1323.167 A (calculated) 500 Easting 500 491.84 = = Northing 500 170.1 172.62 582.059 500

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