A Final exam linkn MENG410 - Final exam xA Lec 14A Lecture notes 12A Lecture notes Part 2A Chapter 10 - Lecture no Xb My Tutoring | bartleby xi ols.liu.edu.lb/mod/quiz/attempt.php?attempt=158760&cmid%3D9485HomeA DashboardEventsMy CoursesThis courseEHide blocks= Quiz navigationThe state of a plane strain at a point has the components Ex = -300 (106), Ey = -400 (10 6) and yyy = 500 (10-6). Determine the equivalent state12357of strain of an element oriented 15° clockwise.Finish attempt ...Select one:Time left 2:29:54Ex = 432 (10-6), Ey = -268 (10-6) and yxy = 483 (10-6).Ex = -432 (10-6), Ey = 268 (10-6) and Yxy = 483 (10-6).Ey = -432 (10-6), Ey = -268 (10-6) and yxy = -483 (10-6).Ex = 432 (10-6), Ey = 268 (10-6) and yxy = -483 (10-6).Ex = -432 (10), Ey = -268 (10-6) and yxy = 483 (10-6).The state of a plane strain at a point has the components Ex = 500 (106), Ey = 250 (10-6)and yyy = 200 (10-6). Determine the principal strains and the maximum in plane shear strain.10.00P FlagquestionSelect one:E1 = -535 (10-6), E2 = -215 (106) and ymax in-plane = -320 (106).E1 = 535 (10-6), E2 = 215 (10) and ymax in-plane = 160 (10-6).E1 = 535 (10-6), E2 = -215 (10-6) and Ymax in-plane = 320 (10-6).E1 = 535 (10 ), E2 = 215 (10 6) and ymax in-plane = 320 (106).E1 = 535 (10-6), Ez = -215 (106) and ymax in-plane = -320 (106).2:05 PMO Type here to search日1/28/2021...

It is required to determine the normal strain in x direction.…

The state of a plane strain at a point has the components ɛ, = -300 (10). ɛy = -400 (106) and Yry = 500 (106). Determine the equivalent state of strain of an element oriented 15° clockwise. Select one: O Ex = 432 (106). Ey = -268 (106) and yry = 483 (106). O &x = -432 (10). Ey = 268 (106) and yy = 483 (10-6). O Ex = -432 (106). ɛy = -268 (10-6) and y,y = -483 (106). Ex = 432 (10-6), Ey = 268 (106) and yxy = -483 (106). O Ex = -432 (10), Ey = -268 (106) and yry = 483 (10-6). %3D The state of a plane strain at a point has the components ɛ, = 500 (10-6). ɛy = 250 (106) and yy = 200 (106). Determine the principal strains and the maximum in plane shear strain. 10.00 P Flag question Select one: E1 = -535 (106), E2 = -215 (106) and ymar in plane = -320 (106). E1 = 535 (10), E2 = 215 (106) and ymax in plane = 160 (106). E = 535 (106), €2 = -215 (10-6) and ymax in- plane = 320 (106). E = 535 (10), E2 = 215 (106) and ymax in plane = 320 (106). E1 = 535 (106). E2 = -215 (10-6) and ymax in-plane = -320 (106).

The state of a plane strain at a point has the components ɛ, = -300 (10). ɛy = -400 (106) and Yry = 500 (106). Determine the equivalent state of strain of an element oriented 15° clockwise. Select one: O Ex = 432 (106). Ey = -268 (106) and yry = 483 (106). O &x = -432 (10). Ey = 268 (106) and yy = 483 (10-6). O Ex = -432 (106). ɛy = -268 (10-6) and y,y = -483 (106). Ex = 432 (10-6), Ey = 268 (106) and yxy = -483 (106). O Ex = -432 (10), Ey = -268 (106) and yry = 483 (10-6). %3D The state of a plane strain at a point has the components ɛ, = 500 (10-6). ɛy = 250 (106) and yy = 200 (106). Determine the principal strains and the maximum in plane shear strain. 10.00 P Flag question Select one: E1 = -535 (106), E2 = -215 (106) and ymar in plane = -320 (106). E1 = 535 (10), E2 = 215 (106) and ymax in plane = 160 (106). E = 535 (106), €2 = -215 (10-6) and ymax in- plane = 320 (106). E = 535 (10), E2 = 215 (106) and ymax in plane = 320 (106). E1 = 535 (106). E2 = -215 (10-6) and ymax in-plane = -320 (106).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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