A three-phase, half-wave uncontrolled rectifier is fed from an ideal three-phase voltage source of 380V, 50 Hz. The load is resistive with R=15 Q. Calculate: (a) The average output voltage and average load current of the rectifier. (b) The d.c. and a.c. power dissipations in the load. (c) The diode ratings.
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- How is a solid-state diode tested? Explain.A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consisting series connected a resistor and an inductance from a 70.7V (RMS), 50HZ sinusoidal AC source. The firing delay of the thyristor is 90° and the load values are R=10Q, L=0.1 H. Define the load current expression and draw the load current by calculating for first two periods. And calculate the average values of the load voltage and current.A single-phase center-tapped rectifier has an R-L of R= 20 0, L = 50mH, and a 240 V ac 50 Hz source voltage. Determine: i. The average and rms currents of the diodes and the load. ii. The rms and average 50 Hz source currents. iii. The power absorbed by the load. iv. The supply power factor.
- H.W:- For a single phase half wave uncontrolled rectifier if the input supply voltage is (v= 310 sin314t), at frequency (f= 50 Hz). Then determine the followings:- Vm. Vmean- i. Draw the rectifier circuit. un %3D ii. Draw the input and the output voltages waveforms. iii. Determine the mean and rms values of the output voltage. s Ec iv. If the load is (R=10 S), then determine the mean and rms values of the current. 2019A three-phase, half-wave uncontrolled rectifier is fed from an ideal three-phase voltage source of 380V, 50 Hz. The load is resistive with R=15 2. Calculate: (a) The average output voltage and average load current of the rectifier. (b) The d.c. and a.c. power dissipations in the load. (c) The diode ratings. (d) What is the lowest ripple frequency of the output voltage waveform?Determine the voltage across the diode, the output voltage, and the current in the resistor in the figure below. Plot these waveforms with proper ac cycle phase alignment. 1SR154-400 is a silicon rectifier 1 ampere diode. Indicate the peak values as per calculation.
- 1. The full-wave rectifier circuit shown in following Figure is to deliver 0.2 A and 12 V (peak values) to a load. The ripple voltage is to be limited to 0.25 V. The input signal is 120 V (rms) at 60 Hz. Assume diode cut-in voltages of 0.7 V. (a) Determine the required turns ratio of the transformer. (b) Find the required value of the capacitor. (c) What is the PIV rating of the diode? vo D23 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RLQ-2: The input signal for half-wave rectifier is a.c. signal. The output of 800 load resistor is 50V d.c. voltage. The diode has a resistance of 25 Q. 5 a) Draw the graphs of input signal, diode signal and output signals. 20 b) Calculate the maximum voltage value for the input signal. AC Supply Diode www
- .Draw a full-wave rectifier circuit (using a diode bridge) and predict the output voltage signal when the input is a sinusoidal signal with amplitude 10 V (p p). Use the previous full wave rectifier to create a peak detector with a 2 V ripple.A three-phase half wave rectifier has a supply of 150V/phase. Determine the mean load voltage and the required diode rating, assuming the load current is level at 25A. Assume each diode has a volt-drop of 0.7V.2. A single-phase single-diode (half wave) rectifier is connected to a 240 V, 50 Hz AC supply. Neglecting the diode volt drop, derive the instantaneous load current equation, determine the current waveform, mean load voltage, and the mean load current for a load of a. Pure resistor of 5 Ohm b. An inductance of 0.1 H in series with 10 Ohm resistor. (clue : B= 265° or 14.72 ms)