A single-stage rocket is launched vertically from rest, and its thrust is programmed to give the rocket a constant upward acceleration of 5.0 m/s2. If the fuel is exhausted 11 s after launch, calculate the maximum velocity Vmax and the subsequent maximum altitude h reached by the rocket. Answers: Vmax h = i i m/s m
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- At the Earth's surface, a projectile is launched straight up at a speed of 7.5 km/s. To what height will it rise? Ignore air resistance. 2.87e+06 Your response differs from the correct answer by more than 10%. Double check your calculations. mA ski jumper starts from rest 45.0 m above the ground on a frictionless track and flies off the track at an angle of 45.0° above the horizontal and at a height of 19.5 m above the ground. Neglect air resistance. (a) What is her speed when she leaves the track? m/s (b) What is the maximum altitude she attains after leaving the track? m (c) Where does she land relative to the end of the track?lo, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plumes of matter over 500 km high. Due to the satellite's small mass, the acceleration due to gravity on lo is only 1.81 m/s², and lo has no appreciable atmosphere. Assume that there is no variation in gravity over the distance traveled ▼ What must be the speed of material just as it leaves the volcano altitude of 310 km? Express your answer in meters per second. V = Submit Part B 1ΫΠ| ΑΣΦ U = Request Answer [5] ΑΣΦ Submit ? If the gravitational potential energy is zero at the surface, what is the potential energy for a 35 kg fragment at its maximum height (500 km) on lo? Express your answer in joules. Request Answer m/s ? Constant J reach an
- A woman bails out of an airplane at an altitude of 15,000 ft, falls freely for 19 s, then opens her parachute. How long will it take her to reach the ground? Assume linear air resistance v ft/s², taking p = 0.15 without the parachute and p = 1.5 with the parachute. (Suggestion: First determine her height above the ground and velocity when the parachute opens.) ww. It will take her seconds to reach the ground. (Round to the nearest whole number as needed.)A ski jumper starts from rest 54.1 m abovethe ground on a frictionless track and fliesoff the track at an angle of 43.8◦above thehorizontal and at a height of 10.8 m above thelevel ground. Neglect air resistance.The acceleration of gravity is 9.8 m/s2.What is his speed when he leaves the track?Answer in units of m/s. b) What is the maximum altitude he attainsafter leaving the track?Answer in units of m. c) Where does he land relative to the end of thetrack?Answer in units of m.The known elevations of the ski jumping hill shown below are as follows: hB = 2.4 m hc = 6.1 m If a ski jumper starts from rest at position A, what elevation (in m) is required at position A to ensure that she reaches a minimum launch velocity of 23.7 m/s at position C [round your final answer to one decimal place]? A C В hc hB
- s On October 9, 1992, a 27-pound meteoritestruck a car in Peekskill, NY, leaving a dent 22 cm deep in thetrunk. If the meteorite struck the car with a speed of 130 m>s,what was the magnitude of its deceleration, assuming it to beconstant?Q.7. A block of mass m = 5 kg starts its motion from point A, 2 m above the %3D ground, with a velocity vA. The block slides down a frictionless incline AB reach- ing B with a velocity vp = 8 m/s. The block then continues its motion on a rough horizontal surface before coming to rest at C. The coefficient of kinetic friction along BC is uk = 0.4. Take g 10 m/s2.The traveled distance d by the block be- tween B and C is: a. d = 12.8 m %3D A m VA b. d = 5 m vg = 8 m/s vc = 0 ha = 2 m c.d = 8 m m i m d. d: = 10.67 m d B+- CA cannon fires a 0.292 kg shell with initial velocity vi = 8.2 m/s in the direction θ = 45 ◦ above the horizontal. The shell’s trajectory curves downward because of gravity, so at the time t = 0.643 s the shell is below the straight line by some vertical distance ∆h. Find this distance ∆h in the absence of air resistance. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.
- Bart Jumps Springfield Gorge on his skateboard. Springfield Gorge us 50m wide, and Bart has constructed a 1.0 m Hugh ramp inclined at 30° to the horizontal. Air resistance is neglected. Homer had calculated that he can jump the gorge if the ramp is inclined to 45°, and he attains a speed of 20m/s. Will Homer make it? If not, how far short of the other side is he when he drops below the level of the ground?The maximum ('terminal') velocity, vt, that a falling object achieves depends on its mass m, the acceleration g due to gravity, the density p of the air, the object's frontal area A, and the object's drag coefficient C, which is a dimensionless quantity. The equation for the terminal velocity is: 2mg V = pCA Part (a): A skydiver jumps out of an airplane (regrettably) without his parachute. To slow his descent, he orients himself in a 'spread eagle' position, thereby increasing his area A to 0.70 m?. His drag coefficient Cis 1.0, which is a unitless quantity. Calculate his terminal velocity in m/s if his mass is 85 kg, the air density p is 1.21 kg/m3, and the constant g is 9.80 m/s?. Show your work, and ensure that each numeric value has the appropriate units. Your answer should be rounded to the appropriate number of significant digits. Part (b): Convert the answer from part (a) to miles per hour using the dimensional analysis method we reviewed in class. Show your work, and ensure…A 1.80x10^4 kg semi-trailer truck drives up a 200 m hill [θ = 30 degrees above horizontal], at a constant speed of 25.0 m/s. The force of friction is 6.00x10^2 N. Write an equation to isolate and solve for P.