The force F has a magnitude of 590 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F. Assume F = 590 N, 0 = 31° Answers: F = (i Fx= i L " i+ N M Mi j) N

Find angle between two unit vectors A and B. A = 10i-3j-15k; B = 13i-5j+3k

Vector math in physics G12. Let vector B have magnitude 5m and direction 60 degrees measured anticloclwise from the positive x-axis. let vector C have the magnatude as vector A and a direction angle 25 degrees higher than A. let dot product AxB=30 square meter and BxC=35 square meters. Find the magnitude and direction of A.

Dot Product, rectangular coordinates: If A = 5 i + -8 j and B = 12 i + 18 j, find A-B

Vector A = 7.2 i + 2.6 j. Vector B = 7.5 i + 7.4 j. The magnitude of the cross product i.e. |AxB| is: :

In the cross (or vector) product F = qu x B we know that q = 1 F = −29î + −16ĵ + −18k 6.01 +3.07 + 7.0k V = B = B + BJ + Bi What then is B in unit-vector notation if Bx = By? B = i î+ i Ĵ+ i

Two vectors are given by a  =  1.5î−4.0ĵ and b  =  −11.9î + 8.1ĵ. What is the magnitude of b? i already found out  magnitude of b is 1.44 but how to calculate the angle between vector b and the positive x-axis?

Page 3 of 8 3. Vector A has a magnitude of 13.6 and is at an angle of 30.5° counterclockwise from the +x- axis. Vector B has a magnitude of 25.1 and is -50.3° from the +x-axis. a. Express the vectors in the unit vector notation and b. find the angle between them.

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Problem 2: Given vectors: A = 3 i+j- k, B = - i+ 2j+ 5 k, C = 2 j - 3 k. Find: 1. C. (A + B) 2. Cx (A - B)