College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- While riding in a hot air balloon, which is steadily descending at a speed of 1.54 m/s, you accidentally drop your cell phone. (a) After 4.00 s, what is the speed of the cell phone? m/s V= (b) How far is the cell phone below the balloon after this time? d = m (c) What are your answers to parts (a) and (b) if the balloon is rising steadily at 1.54 m/s? m/s d =arrow_forwardA flashlight is thrown straight up on the Moon at 30.0 m/s. The acceleration due to gravity at the surface of the Moon is 1.62 m/s2, and the Moon has no atmosphere. What is the height of the flashlight when it is coming back down with a speed of 20.0 m/s?arrow_forwardA rock is thrown straight up into the air with an initial speed of 85 m/s at time t = 0. Ignore air resistance in this problem. At what times does it move with a speed of 13 m/s? Note: There are two answers to this problem.arrow_forward
- An elevator is initially moving upward at a speed of 13 m/s. The elevator experiences a constant downward acceleration of magnitude 3.5 m/s2 for 2.5 s. You will be asked to find the elevator's final velocity. What are the givens? Group of answer choices a = -3.5 m/s2, v0 = 13 m/s, t = 2.5 s a = 3.5 m/s2, v0=13 m/s, t = 2.5 s a = 3.5 m/s2, v0=13 m/s, vf = 0 m/s a = -3.5 m/s2, vf=0 m/s, t = 2.5 sarrow_forwardConsider a grey squirrel falling from a tree to the ground. Use a coordinate system in which positive is downward for this problem. a) Find the squirrel’s velocity, in meters per second, just before hitting the ground when it falls from a height of 1.3 m. Ignore air resistance. b) The squirrel softens its landing by bending its legs when it touches the ground, thereby stopping itself over a distance of 7.6 cm. Assuming a constant rate of deceleration, find the squirrel’s acceleration during this process, in meters per second squared.arrow_forwardWhen the effect of aerodynamic drag is included, the y-acceleration of a baseball moving vertically upward is au = -g - kv², while the acceleration when the ball is moving downward is ad=-g+kv², where k is a positive constant and v is the speed in meters per second. If the ball is thrown upward with an initial speed of 40 m/s, determine the time tu from ground to apex and the time to from apex to ground. Take k to be 0.006 m¹ and assume that g is constant. au=-g-kv² Answers: tu = td = i i 40 m/s ad=-g+kv² S S harrow_forward
- A pole vaulter is momentarily motionless as he clears the bar, which is set 4.2 m above the ground. He then falls onto a thick cushion. The top of the cushion is 80 cm above the ground, and it compresses by 50 cm as the pole vaulter comes to rest. What is his acceleration as he comes to rest on the cushion?arrow_forwardAn object accelerating at constant acceleration (a) has an initial velocity v0 (at t=0), a velocity v at time t, and goes a particular distance d or x - x0 during the time interval. Derive the expression relating v0, v, a, and d (or x-x0). The relation must not include time. You may use either algebra or calculus.arrow_forwardA small mailbag is released from a helicopter that is descending steadily at 1.76 m/s. (a) After 5.00 s, what is the speed of the mailbag? V = m/s (b) How far is it below the helicopter? d = m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.76 m/s? m/s V = d = marrow_forward
- How long does it take to hit the ground?arrow_forwardstarting from rest, a rocket is launched upward (a=4.20 m/s^2). At t=6.85 sec, the motor shuts off the rocket continues to coast upward until it reached its highest point. At highest point, a chute was introduced so that the rocket will fall at a constant speed of 0.935 m/s until it reaches the ground. Determine the maximum height, h, in metersarrow_forwardSome troublemaking kids are dropping water balloons from the roof of your apartment building. You are in your fifth-floor room and your window is 25 m above the sidewalk outside. You look outside and see that each balloon hits the pavement 1.5 s after passing your window. Express answers using 2 significant figures. a) How fast are the balloons traveling when they pass your window? b) Assuming the balloons are being released from rest, from what height above your window are they being released? c) If you threw a balloon upwards from your window with an initial speed of 6.5 m/s, would you be able to get it to the roof?arrow_forward
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