A screen is placed a distance d to the right of an object. A converging lens with focal length f is placed between the object and the screen. In terms of f , what is the smallest value d can have for an image to be in focus on the screen?

A diverging lens is located 14 cm to the left of a converging lens. A 3.44-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens, in cm. Diverging lens 1 focal length = -7 cm Converging lens 2 focal length = 32 cm Object F1 Lens 1 Round to nearest whole number Lens 2 Eye A

In order to heighten your enjoyment of your 29 carat blue diamond, you view it through a lens held close to your right eye at an angular magnification of 5.1. The distance of your right eye's near point is 25 cm.  What is the focal length f of the lens in centimeters? f = ?cm

It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won'’t work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can'’t be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…