A +2.0 D lens is being used to make an image of a distant object on a screen. The image is 2.4 cm tall. A second +2.0 D lens is added to the first, and the lens combination is moved to refocus the image. How tall is the new image?

A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College Physic

A converging lens and a diverging lens, separated by a distance of 30.0 cm, are used in combination. The converging lens has a focal length of 15.3 cm. The diverging lens is of unknown focal length. An object is placed 19.5 cm in front of the converging lens; the final image is virtual and is formed 12.0 cm in front of the diverging lens. What is the focal length of the diverging lens?

Two lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1.   Find the location of the final image of the object. What is the magnification of the final image?