An object is placed 40 cm from a converging lens with a focal length of 20 cm. The image formed by this lens becomes the object for a second diverging lens with a focal length of −15 cm. The distance between the two lenses is 50 cm. Calculate the final image distance formed by this two-lens system. Draw a diagram of the optical system.

You use a lens to form an image. The object is 50 cm from the lens and the image is formed at a position of -14 cm. What is the focal length of your lens? f = cm What is the magnification of the lens? m = Is the image formed real or virtual? --- Is the image upright or inverted? Are you using a converging lens or a diverging lens?

A concave lens has a focal length of -7 cm. A candle with a height of 5 cm is 25 cm away from the lens. Find the location of the image. If the image is real give a positive answer and a virtual image should be a negative answer.

Two lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1.   Find the location of the final image of the object. What is the magnification of the final image?

Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.

An object (height = 5.0 cm) and its image are on opposite sides of a converging lens. The object is located 11.0 cm from the lens. The image is located 5.3 cm from the lens. Determine the image height (in cm). Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the image height is significant.

A spherical concave lens has a focal length of 50 cm, and an object is placed 25 cm from the lens. Draw a digram.  Estimate the image distance Is it real or virtual upright or inverted magnified or reduced

An object is 6 cm in front of a converging lens with a focal length of 10cm. Draw a ray diagram (to scale with a ruler) to find the location of the image. Is the image upright or inverted, and Is the image real or virtual? Then I want to use the thin lens formula to find the image distance and the magnification. I got stuck in the middle of this problem and am confused. Thank you for the help!

A converging lens of focal length f=2 cm is used to focus the image of an object onto a screen. The object and screen are separated by 15 cm. The lens is placed between the object and the screen, at a distance from the screen such that the image of the object is focused into the screen. At what distance from the screen must the lens be placed in order to have an image magnification < 1? Provide your answer to two significant figures. distance = cm.