A candle is placed at a fixed distance D from a screen. A converging lens can be put between the screen and the candle, at a variable distance x from the candle. Assume a sharp image occurs on the screen. (A) If the magnification is 2, what is x? (B) If the magnification is 1/2, what is x? (C) What is the focal length of the lens? HINT: Draw ray diagrams. D = 87 cm. larification: the absolute value of the magnification is either 2 or 1/2.]

You want to purchase a microscope for doing surgeries, which requires that there is at least 10cm distance between the objective lens and the patient. The objective forms a highly magnified real image of the object at a distance L. You want the image to look 50 times larger. What should be focal lengths of the objective and the eye piece assuming L=200mm

An object of height 5.50 cm is placed 33.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? O real virtual (e) Is the image upright or inverted? O upright O inverted

A lightbulb is 4.0 m from a wall. Part A: What is the focal length of a lens what will form an image on the wall that is twice the size of the lightbulb? Part B: What is the position (measured from the bulb) of the lens? Thank you in advance!

A convex lens made of glass (n = 1.50) has a focal distance of 20 cm. An identical looking piece of plastic with same shape and thickness has a focal distance of 25 cm. Which of the following could be the index of refraction of the plastic? O 1.0 O 1.4 O 1.6 O 1.5

An object is placed 27 cm in front of a diverging lens having a focal length of magnitude 50 cm. What is the image distance, in cm?  Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.

A transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.

Homework 12 Problem 10:   Two lenses are mounted d = 27 cm apart on an optical bench. The focal length of the first lens is f1 = 5.1 cm and that of the second lens is f2 = 4.4 cm. An object of height ho = 3.5 cm is placed at a distance of do = 21 cm in front of the first lens. Part (a)  Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di = ______ Part (b)  Calculate the magnification of that image, including its sign. m = ______ Part (c)  Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D = ______

An object is 6 cm in front of a converging lens with a focal length of 10cm. Draw a ray diagram (to scale with a ruler) to find the location of the image. Is the image upright or inverted, and Is the image real or virtual? Then I want to use the thin lens formula to find the image distance and the magnification. I got stuck in the middle of this problem and am confused. Thank you for the help!

A converging lens of focal length f=2 cm is used to focus the image of an object onto a screen. The object and screen are separated by 15 cm. The lens is placed between the object and the screen, at a distance from the screen such that the image of the object is focused into the screen. At what distance from the screen must the lens be placed in order to have an image magnification < 1? Provide your answer to two significant figures. distance = cm.