A researcher uses a sample of n = 25 individuals to evaluate the effect of a treatment. The hypothesis test uses a = .05 and produces a significant result with t = 2.15. How would the statistical sentence be reported? a. t(25) = 2.15, p < .05 b. t(24) = 2.15, p < .05 c. t(25) = 2.15, p > .05 (incorrect answer) d. t(24) = 2.15, p > .05

I need help asap. This is the question.  A recent study at a local college claimed that the porportion, p, of students  who commute more than 15 miles to school  is no more than 15% . If a random  sample of 175 students  at this college  is selected,  and it is found that 86 commute more than 15 miles to school, can we reject the college's claim at the 0.05 level of significance.  Perform 1 failed test then fill in the table below

Would you favor spending more federal tax money on the arts? Of a random sample of n1 = 217 women, r1 = 52 responded yes. Another random sample of n2 = 175 men showed that r2 = 48 responded yes. Does this information indicate a difference (either way) between the population proportion of women and the population proportion of men who favor spending more federal tax dollars on the arts? Use ? = 0.05. (a) What is the level of significance?   (b) What is the value of the sample test statistic? (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)

Would you favor spending more federal tax money on the arts? Of a random sample of n1 = 232 women, r1 = 66 responded yes. Another random sample of n2 = 198 men showed that r2 = 65 responded yes. Does this information indicate a difference (either way) between the population proportion of women and the population proportion of men who favor spending more federal tax dollars on the arts? Use ? = 0.05.   (a) What is the level of significance?State the null and alternate hypotheses. H0: p1 = p2; H1: p1 ≠ p2H0: p1 < p2; H1: p1 = p2    H0: p1 = p2; H1: p1 > p2H0: p1 = p2; H1: p1 < p2 (b) What sampling distribution will you use? What assumptions are you making? The Student's t. We assume the population distributions are approximately normal.The standard normal. We assume the population distributions are approximately normal.    The standard normal. The number of trials is sufficiently large.The Student's t. The number of trials is sufficiently large. What is the value of the sample…

Which of the following is the correct way to report the results of a hypothesis test and a measure of effect size using a tstatistic?​     a. ​r2 = 0.42, t(19) = 2.30 , p < .05   b. ​t(19) = 2.30, p < .05, r2 = 0.42   c. ​t = 2.30, df = 19, p < .05, r2 = 0.42   d. ​t(19) = 2.30, r2 = 0.42, p < .05

Referring to the example below If a compliance rate of 95% is expected how many of the 750 charts requested could fall below the standard and still be within the 95% goal An him department has 50,000 active records on file the record supervisor has established a maximum 15 minute time. For retrieval of a record during the past month 750 charts were requested of this number 688 where retrieved within a 15 minute. What percentage of the records fell below the established standard subtracting 688 from 750 indicates that 62 charts did not meet the required standard bus 62 out of 750 retrievals were not in compliance for an 8.27% non-compliance rate

A medical equipment manufacturer believes that the proportion of faulty blood pressure monitors is greater than 0.11, the proportion stated by the supplier. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.11 and Ha: p < 0.11. A researcher inspects 150 items and finds 25 faulty ones. She gives a p-value of 0.01 in her analysis. Which of the following definitions is the correct interpretation of the p-value? O The probability of getting 25 or more faulty blood pressure monitors out of 150 if the true faulty rate is 0.11. The value that the z-statistic must be less than in order to reject the null hypothesis. The probability of rejecting a true null hypothesis. O The probability that the true rate of faulty items is 0.01.

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In a fishing lodge brochure, the lodge advertises that 75% of its guests catch northern pike over 20 pounds. Suppose that last summer 71 out of a random sample of 86 guests did, in fact, catch northern pike weighing over 20 pounds. Does this indicate that the population proportion of guests who catch pike over 20 pounds is different from 75% (either higher or lower)? Use ? = 0.05.   (a) What is the level of significance?   State the null and alternate hypotheses. H0: p = 0.75; H1: p > 0.75H0: p ≠ 0.75; H1: p = 0.75    H0: p < 0.75; H1: p = 0.75H0: p = 0.75; H1: p ≠ 0.75H0: p = 0.75; H1: p < 0.75 (b) What sampling distribution will you use? The Student's t, since np > 5 and nq > 5.The standard normal, since np > 5 and nq > 5.    The Student's t, since np < 5 and nq < 5.The standard normal, since np < 5 and nq < 5. What is the value of the sample test statistic? (Round your answer to two decimal places.)   (c) Find the P-value of the test…

Would you favor spending more federal tax money on the arts? Of a random sample of n1 = 204 women, r1 = 70 responded yes. Another random sample of n2 = 178 men showed that r2 = 48 responded yes. Does this information indicate a difference (either way) between the population proportion of women and the population proportion of men who favor spending more federal tax dollars on the arts? Use ? = 0.05.   (a) What is the level of significance?State the null and alternate hypotheses. H0: p1 = p2; H1: p1 > p2H0: p1 = p2; H1: p1 < p2    H0: p1 = p2; H1: p1 ≠ p2H0: p1 < p2; H1: p1 = p2 (b) What sampling distribution will you use? What assumptions are you making? The standard normal. We assume the population distributions are approximately normal.The Student's t. The number of trials is sufficiently large.    The standard normal. The number of trials is sufficiently large.The Student's t. We assume the population distributions are approximately normal. What is the value of the sample…