Suppose you carry out a significance test of H0: μ = 8 versus Ha: μ > 8 based on sample size n = 25 and obtain t = 2.15. Find the p-value for this test. What conclusion can you draw at the 5% significance level? Explain. Group of answer choices The p-value is 0.02. We reject H0 at the 5% significance level because the p-value 0.02 is less than 0.05. The p-value is 0.02. We fail to reject H0 at the 5% significance level because the p-value 0.02 is less than 0.05. The p-value is 0.48. We reject H0 at the 5% significance level because the p-value 0.48 is greater than 0.05. The p-value is 0.48. We fail to reject H0 at the 5% significance level because the p-value 0.48 is greater than 0.05. The p-value is 0.52. We fail to reject H0 at the 5% significance level because the p-value 0.52 is greater than 0.05.

p value for B please

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.57. You use a significance level of a = 0.001. Ho:p = 0.57 H1:p > 0.57 You obtain a sample of size n = 331 in which there are 211 successes.

You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.15. You use a significance level of a = 0.01. Но:р — 0.15 H1:p > 0.15 You obtain a sample of size n 137 in which there are 28 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is.. less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that. O There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. O There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. The sample data support…

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level. The alternative hypothesis would be: p 0.8 u > 0.8 µ < 0.8 p # 0.8 µ # 0.8 o The test is: left-tailed two-tailed right-tailed Based on a sample of 500 people, 75% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals)

You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly less than 0.52. You use a significance level of a = 0.01. Ho:p = 0.52 H1:p < 0.52 You obtain a sample of size n = 414 in which there are 208 successes. What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a This p-value leads to a decision to... reject the null accept the null O fail to reject the null

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You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 0.16. You use a significance level of a = 0.01. Но:р — 0.16 H1:p > 0.16 You obtain a sample of size n = 621 in which there are 104 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads to a decision to... O reject the null O accept the null Ofail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.16. O There is not sufficient evidence to warrant rejection of the claim that the proportion of voters who prefer Candidate A is more than 0.16. O The sample data support the claim that the…

Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…