In a survey, 33% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too high, so he randomly selected 150 pet owners and discovered that 46 of them spoke to their pet on the telephone. Does the veterinarian have a right to be skeptical? Use the x = 0.01 level of significance. Because npo (1-Po) = population size, and the sample ... 10, the sample size is requirements for testing the hypothesis (Round to one decimal place as needed.) satisfied. 5% of the the

The table below summarizes data from a survey of a sample of women. Using a 0.01 significance​ level, and assuming that the sample sizes of 900 men and 400 women are​ predetermined, test the claim that the proportions of​ agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of​ women?                 Gender of Interviewer         Man Woman     Women who agree   625 330     Women who disagree   275 70     Compute the test​ statistic, rounding to three decimal places. Find the critical​ value(s). (Round to three decimal places) What is the conclusion based on the hypothesis​ test?

The Bureau of Labor Statistics reports that the official unemployment rate for Black people was 10.4% and 4.7% for White people in February 2015. Select all correct answers for this question. O The samples of white and black people are independent. The explanatory variable is the unemployment rate. The response variable is the unemployment rate. The response variable is race.

The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.)   t  =    Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…