MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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### Analyzing Police Call Frequencies by Day of the Week

A police department released the numbers of calls for the different days of the week during the month of October, as shown in the table below. The goal is to test the claim at a 0.01 significance level that the different days of the week have the same frequencies of police calls. We will analyze the data below and identify the fundamental error with this analysis.

#### Call Frequency Table

| Day  | Frequency |
|------|-----------|
| Sun  | 160       |
| Mon  | 210       |
| Tues | 227       |
| Wed  | 246       |
| Thurs| 172       |
| Fri  | 208       |
| Sat  | 234       |

#### Hypothesis Testing

**Determine the null and alternative hypotheses:**

- \( H_0 \): 
- \( H_1 \): 

**Calculate the Chi-square test statistic, \( \chi^2 \):**

\[ \chi^2 = \] (Round to three decimal places as needed.)

**Calculate the P-value:**

\[ \text{P-value} = \] (Round to four decimal places as needed.)

**What is the conclusion for this hypothesis test?**

- **Option A**: Reject \( H_0 \). There is insufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.
- **Option B**: Reject \( H_0 \). There is sufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.
- **Option C**: Fail to reject \( H_0 \). There is insufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.
- **Option D**: Fail to reject \( H_0 \). There is sufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

#### Identifying the Fundamental Error in the Analysis

**What is the fundamental error with this analysis?**

- **Option A**: Because October has 31 days, each day of the week occurs the same number of times as the other days of the week.
- **Option B**: Because October has 31 days, three of the days of the week occur more often than the other days of the week.
- **Option
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Transcribed Image Text:### Analyzing Police Call Frequencies by Day of the Week A police department released the numbers of calls for the different days of the week during the month of October, as shown in the table below. The goal is to test the claim at a 0.01 significance level that the different days of the week have the same frequencies of police calls. We will analyze the data below and identify the fundamental error with this analysis. #### Call Frequency Table | Day | Frequency | |------|-----------| | Sun | 160 | | Mon | 210 | | Tues | 227 | | Wed | 246 | | Thurs| 172 | | Fri | 208 | | Sat | 234 | #### Hypothesis Testing **Determine the null and alternative hypotheses:** - \( H_0 \): - \( H_1 \): **Calculate the Chi-square test statistic, \( \chi^2 \):** \[ \chi^2 = \] (Round to three decimal places as needed.) **Calculate the P-value:** \[ \text{P-value} = \] (Round to four decimal places as needed.) **What is the conclusion for this hypothesis test?** - **Option A**: Reject \( H_0 \). There is insufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls. - **Option B**: Reject \( H_0 \). There is sufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls. - **Option C**: Fail to reject \( H_0 \). There is insufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls. - **Option D**: Fail to reject \( H_0 \). There is sufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls. #### Identifying the Fundamental Error in the Analysis **What is the fundamental error with this analysis?** - **Option A**: Because October has 31 days, each day of the week occurs the same number of times as the other days of the week. - **Option B**: Because October has 31 days, three of the days of the week occur more often than the other days of the week. - **Option
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