A particle moves along one dimension with a constant acceleration of 4.30 m/s2 over a time interval. At the end of this interval it has reached a velocity of 13.2 m/s. (a)If its original velocity is 6.60 m/s, what is its displacement (in m) during the time interval? (b)What is the distance it travels (in m) during this interval? (c)A second particle moves in one dimension, also with a constant acceleration of 4.30 m/s2 , but over some different time interval. Like the first particle, its velocity at the end of the interval is 13.2 m/s, but its initial velocity is −6.60 m/s. What is the displacement (in m) of the second particle over this interval? (d) What is the total distance traveled (in m) by the second particle in part (c), during the interval in part (c)?

The graph shows the displacement-time history for the rectilinear motion of a particle during an 8-second interval. Determine the average velocity vay during the interval and, to within reasonable limits of accuracy, find the instantaneous velocity v when t = 4 s. 8, m 10 8 00 6 4 2 0 0 Answers: 2 4 t, s When t = 4 s, 6 For the whole interval, Vav= V = 8 m/s m/s

The position of a particle moving along an x axis is given by x = 16.0t2 - 5.00t3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 5.00 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f)What is the maximum positive velocity reached by the particle and (g) at what time is it reached? (h) What is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)? (i) Determine the average velocity of the particle between t = 0 and t = 5.00 s.

A person walks 20.0 meters in a straight line. Then the person turns around and walks back 18.0 meters along the same line. The time for the walk is 9.00 seconds.(a) What is the average speed for this walk?(b) What is the average velocity for this walk?(c) What is the displacement?(d) What is the total distance?

A particle moves along one dimension with a constant acceleration of 3.45 m/s2 over a time interval. At the end of this interval it has reached a velocity of 10.2 m/s. (a) If its original velocity is 5.10 m/s, what is its displacement (in m) during the time interval?   m (b) What is the distance it travels (in m) during this interval?   m (c) A second particle moves in one dimension, also with a constant acceleration of 3.45 m/s2 , but over some different time interval. Like the first particle, its velocity at the end of the interval is 10.2 m/s, but its initial velocity is  −5.10 m/s.  What is the displacement (in m) of the second particle over this interval?   m (d) What is the total distance traveled (in m) by the second particle in part (c), during the interval in part (c)?  m

The position of a particle moving along an x axis is given by x = 13.0t2 - 6.00t3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 4.00 s. (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) What is the maximum positive velocity reached by the particle and (g) at what time is it reached? (h) What is the acceleration of the particle at the instant the particle is not moving (other than at t = 0)? (i) Determine the average velocity of the particle between t = 0 and t = 4.00 s.(a).=-176m(b).=-184m/s (c).=-118.0m/s^2 (d).=9.041m (e).=1.444s (f).=9.389m/s (g).=0.722sPlease help me with h and i.

The position of a particle in millimeters is given by s = 112 - 23t+t² where t is in seconds. Plot the s-t and v-t relationships for the first 16 seconds. Determine the net displacement As during that interval and the total distance D traveled. By inspection of the s-t relationship, what conclusion can you reach regarding the acceleration?

A train is slowing down as it travels along a straight, level track. A uniform acceleration of 1.25 m/s² was achieved as the train slowed down so that the final speed of the train is 20 km/h after traveling a distance of 35 m. (a) What was the speed of the train at the beginning of this distance? (b) How long did it take for the train to travel the 35 m? (c) Include a complete

A particle moving along a straight line has initial velocity v(0) = 1 m/s, and acceleration a(t) = sin(I-t) + cos(t+1) (in m/s?). (a. Find the velocity at time t. (b) Find the average velocity during the time interval [I, 211]. (c) Find the distance traveled during the time interval [1, 2I].