A particle moves along one dimension with a constant acceleration of 4.30 m/s2 over a time interval. At the end of this interval it has reached a velocity of 13.2 m/s. (a)If its original velocity is 6.60 m/s, what is its displacement (in m) during the time interval? (b)What is the distance it travels (in m) during this interval? (c)A second particle moves in one dimension, also with a constant acceleration of 4.30 m/s2 , but over some different time interval. Like the first particle, its velocity at the end of the interval is 13.2 m/s, but its initial velocity is −6.60 m/s. What is the displacement (in m) of the second particle over this interval? (d) What is the total distance traveled (in m) by the second particle in part (c), during the interval in part (c)?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Given:
The acceleration of the first particle is a1 = 4.3 m/s2
The final velocity of the first particle is v1 = 13.2 m/s
The initial velocity of the first particle is u1 = 6.6 m/s
The acceleration of the second particle is a2 = 4.3 m/s2
The final velocity of the second particle is v2 = 13.2 m/s
The initial velocity of the second particle is u2 = - 6.6 m/s
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