A motorboat is traveling at a constant velocity of 6.0 m/s when it starts to decelerate to arrive at the dock. Its acceleration is a(t) = -tm/s² (a) What is the velocity function of the motorboat? (b) At what time does the velocity reach zero? (c) What is the position function of the motorboat?

Please answer all question parts: A Lockheed Martin F-35 Lightning II jet takes off from an aircraft carrier with a runway length of 97 m and a takeoff speed 72 m/s at the end of the runway. Jets are catapulted into airspace from the deck of an aircraft carrier with two sources of propulsion: the jet propulsion and the catapult. At the point of leaving the deck of the aircraft carrier, the F-35's acceleration decreases to a constant acceleration of 4.3 m/s2 at 33° with respect to the horizontal. (Assume that the F-35's initial direction along the deck of the aircraft carrier is the +x-direction and that the +y-direction is up.) (a) What is the initial acceleration (in m/s2) of the F-35 on the deck of the aircraft carrier to make it airborne? (Enter the magnitude.) (b) Write the position (in m) and velocity (in m/s) of the F-35 in unit vector notation from the point it leaves the deck of the aircraft carrier. (Use the following as necessary: t.) (c) At what altitude (in m) is…

A stone is thrown upward with an initial velocity of 128 ft/s from the roof of a building 320 ft high. Express its height above the ground as a function of time. Find the following:  a) The maximum height that the stone reaches b) The time it takes for the stone to hit the ground c) The velocity and speed of the stone when it hits the ground

A rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 2.8 seconds the rocket is at a height of 91 meters. (A) What are the magnitude and direction of the rocket's acceleration? (B) What is it's speed at this time? Can you please solve the question using one or more of these equations: v = v0 +at vav = (1/2) times (v0 + v) x = x0 + (1/2) times (v0 + v) times t x = x0 + v0t + (1/2)at2 v2 = v02 + 2a(x - x0)

An automobile travels on a straight road for 34 km at 36 km/h. It then continues in the same direction for another 34 km at 72 km/h. (a) What is the average velocity of the car during this 68 km trip? (Assume that it moves in the positive × direction.) (b) What is the average speed?

A particle moves in one dimension, and its position as a function of time is given by x (2.0 m/s)t + (-3.6 m/s²)e². (a) What is the particle's average velocity from t 0.45 s to t = 0.55 s? (Indicate the direction with the sign of your answer.) m/s (b) What is the particle's average velocity from t = 0.49 s to t = 0.51 s? (Indicate the direction with the sign of your answer.) m/s MacBook Air 888 F1 F2 F3 F4 F5 F6 @ #3 $4 3 4 Q W E R T G

Assume you are driving a car at a constant speed of 76 km/h. Suddenly you see a deer standing on the highway and you must put on the brakes. Your reaction time (time elapsed between the moment you see the deer and your foot hitting the brakes) is 0.118 s. The brakes provide an acceleration with a magnitude of 4 m/s2, and a direction opposite the initial velocity.   How do you find the total distance traveled?

The velocity of a particle traveling in a straight line is given by v = (6t – 3t²) m/s, where t is in seconds. If s = 0 when t = 0, determine the particle's deceleration and position when t = 5 s. How far has the particle traveled during the t = 5 s time interval, and what is its average speed? I need a clear answer by hand, not by keyboard | dybala