A large wooden wheel (mass 2 kg, radius 0.5 m) is mounted on an axle so as to rotate freely about its center. A bullet of mass and speed(10g,100m/s)  is shot and moves in a straight line (neglect gravity) tangential to the wheel and strikes its edge, lodging in it at the rim. The wheel is initially at rest. Your goal is to figure out how fast it will rotate after the collision. What is the initial angular momentum of the system (bullet + wheel)? After the bullet lodges in the rim, what is the moment of inertia of the bullet + wheel? What is the final angular speed of the wheel?

A projectile of mass .050 kg moves to the right with a speed of 4.0 m/s. The projectile strikes and sticks to the end of a rod of mass 0.8 kg, at length 1.2 m from the rod's centre. The rod may rotate freely around a stationary axle pinned through the rod's centre of mass. Find the magnitude of the angular velocity, ω, of the system right after the collision.

A bicycle is traveling north at 6.84 m/s. The mass of the wheel, 2.6 kg, is uniformly distributed along the rim(I=mr2), which has a radius of 17.89 cm. What are the magnitude(in kg m2/s) and direction of the angular momentum of the wheel about its axle?

The figure shows a small piece of clay colliding into a disk. The disk is initially at rest, but can rotate about a pivot fixed at its center. The collision is completely inelastic.1) The disk has mass M = 4.73 kilograms and radius R = 0.755 meters. The clay has mass m = 279 grams and is moving horizontally at vi = 3.66 m/s just before colliding with and sticking to the disk. The clay strikes the edge of the disk at a location of b = 0.505 meters offset from the center of the disk. Note that the size of the clay is negligible compared to the radius of the disk. 2) Calculate the angular velocity (rad/s) of the disk just after the collision.