College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Consider an isolated system moving through empty space. The system consists of objects that interact with each other and can change location with respect to one another. Which of the following quantities can change in time? Both the angular momentum and linear momentum of the system The angular momentum of the system Neither the angular momentum nor linear momentum of the system O The linear momentum of the systemarrow_forwardA point mass m1 = 0.020 kg located at the top corner of a smooth hemispherical bowl m, R. of radius R = 0.450 m is released from rest and hits another point mass m2 = 0.010 kg m2 which is at rest at the bottom of the bowl as shown in the figure. If two masses stick together after the collision, how high above do they go relative to the bottom of the bowl? (Ignore the friction between the %3D masses and the surface of the bowl and take g = 9.8 m/s.)arrow_forwardAngular momentum is conserved for this inelastic collision because the surface is frictionless and the unbalanced external force at the nail exerts no torque. The disk has a mass of 51.5 g and an initial velocity of 32.0 m/s when it strikes the stick that is 1.40 m long and 2.05 kg at a distance of 0.100 m from the nail. 1. What is the angular velocity (in rad/s) of the two after the collision? (magnitude in rad/s) 2. What is the kinetic energy (in J) before and after the collision? Kbefore= J Kafter= J 3. What is the total linear momentum (in kg · m/s) before and after the collision? (Entermagnitude) pbefore= kg · m/s pafter= kg · m/sarrow_forward
- The figure shows a small piece of clay colliding into a disk. The disk is initially at rest, but can rotate about a pivot fixed at its center. The collision is completely inelastic.The disk has mass M = 4.84 kilograms and radius R = 0.74 meters. The clay has mass m = 285 grams and is moving horizontally at vi = 3.88 m/s just before colliding with and sticking to the disk. The clay strikes the edge of the disk at a location of b = 0.505 meters offset from the center of the disk. Note that the size of the clay is negligible compared to the radius of the disk. 1. Calculate the angular speed (rad/s) of the disk just after the collision.arrow_forwardAs part of a carnival game, a my = 0.653 kg ball is thrown at a stack of 23.8 cm tall, mo = = 0.363 kg objects and hits with a perfectly horizontal velocity of Ubi = 10.8 m/s. Suppose that the ball strikes the topmost object. Immediately after the collision, the ball has a horizontal velocity of bf = 3.10 m/s in the same direction, the topmost object has an angular velocity of @= 1.63 rad/s about its center of mass, and all the remaining objects are undisturbed. Assume that the ball is not rotating and that the effect of the torque due to gravity during the collision is negligible. If the object's center of mass is located r = 16.7 cm below the point where the ball hits, what is the moment of inertia I, of the object about its center of mass? What is the center of mass velocity Uo.cm of the tall object immediately after it is struck? (1) 0 Io = b.J Vo.cm = kg-m² m/sarrow_forwardA gymnast with a mass of 55 kg flipped in the air and achieved a maximum angular velocity of 445 degrees/sec just before landing from the flip. a) What is the magnitude of the angular impulse in kg*m2/s exerted by the floor on the gymnast when they stuck the landing and came to a complete stop, if they had a radius of gyration of 0.75 meters throughout the landing and their initial angular velocity just as they hit the floor was equal to the maximum angular velocity of 445 degrees/sec?arrow_forward
- A horizontal force is applied over a small interval of time to the systern of particles in the situations shown, Before the application of the impulse to after the removal of the impulse: A B C D 771 77 FAr FAr m 77 0.5FAr m FAr 27m Which has least magnitude of the change in angular velocity of each body's mass center? O Aarrow_forwardSolve with illustration.arrow_forwardA 0.00600 kg bullet traveling horizontally with speed 1.00 103 m/s strikes a 16.0 kg door, embedding itself 11.9 cm from the side opposite the hinges as shown in the figure below. The 1.00 m wide door is free to swing on its frictionless hinges. Imagine that the door is hanging vertically downward, hinged at the top, so that the figure is a side view of the door and bullet during the collision. What is the maximum height (in cm) that the bottom of the door will reach after the collision?arrow_forward
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